1252 Chapter 34
,LR is the reverberant level in the 2 kHz octave band,
LD is the direct sound level in the 2 kHz octave band,
LN is the ambient noise level in the 2 kHz octave band.
34.2.3.4.5 Question 4: Will It Feed Back?
The PAG and NAG concepts work indoors, too, but are
modified by the room.
(34-21)where,
,other terms are as before.
Example:
Let,
Ds = 2 ft,
Do = 128 ft,
D 1 = 45 ft,
D 2 = 90 ft,
Dc = 31.2 ft,
NOM = 3.
To compare to the simplified (outdoor) system PAG Eq.
34-5, simply ignore the term
(34-22)where,
,other terms are as before.
Example:
Let
Do = 128 ft,
EAD = 4 ft,
Dc = 31.2 ft.To compare to Eq. 34-8, simply ignore the termAlternate forms of the PA G and NAG equations,
which are more common in the literature, follow:(34-23)where,where,
x is any distance,
other terms are as before.Example:
Let
Do = 128 ft,
D 1 = 45 ft,
Ds = 2 ft,
D 2 = 90 ft,
Q = 5,
S = 28,000 ft^2 ,
a = 0.35,
NOM = 3.Thenand(34-24)
where,EN 10LN
=^10 ------ -PAG 20D 0 D 1
DsD 2log-------------– 10 logNOM6 dB10gD 0 gD (^1)
gD (^) sgD (^2)
- log------------------------------
=gx Dc^2 += x^2PAG 20 128 45^
290log--------------------–6 dB 10 3log –10 17,357 2998^
977 9073log-----------------------------------= –=11.7 dB.10gD (^) ogD (^1)
gD (^) SgD (^2)
- log------------------------------
NAG 20Do
EADlog------------ 10gD (^) o
g EAD
= – log--------------------
gx Dc^2 += x^2
NAG 20 128
4
log--------- 10 g^ 17,357
g 989
= – log------------------------
=17.7 dB
10
gD (^) o
g EAD
- log--------------------
PAG 'Do 'D 1 – 'Ds 'D 2
10- logNOM
- 6 dB
+='x 10 Q
4 Sx----------- 2 -
4
Sa–= log©¹§·--------+'Do =33.6,
'D 1 =32.2,'Ds=10.0,
'D 2 =33.4,PAG 33.6+= 33.2 10– –633.4 10–3log – dB
=11.7 dBNAG 'Do–= 'EAD