NCERT Class 10 Mathematics

36 MATHEMATICS So, 2x^4 – 3x^3 – 3x^2 + 6x – 2 = (x^2 – 2)(2x^2 – 3x + 1 ). Now, by splitting –3x, we factorise 2x^2 – 3x + 1 as ...

POLYNOMIALS 37 If the zeroes of the polynomial x^3 – 3x^2 + x + 1 are a – b, a, a + b, find a and b. If two zeroes of the polyn ...

3 3.1 Introduction You must have come across situations like the one given below : Akhila went to a fair in her village. She wan ...

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES 39 Let us try this approach. Denote the number of rides that Akhila had by x, and the ...

40 MATHEMATICS In fact, this is true for any linear equation, that is, each solution (x, y) of a linear equation in two variable ...

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES 41 Fig. 3.1 Both ways of representing a pair of linear equations go hand-in-hand — the ...

42 MATHEMATICS equation in one variable, which can be solved easily. For instance, putting x = 0 in Equation (2), we get 4y = 20 ...

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES 43 Fig. 3.3 These solutions are given below in Table 3.2. Table 3.2 x 0 4.5 x 03 y = 9 ...

44 MATHEMATICS We observe in Fig. 3.4, that the lines do not intersect anywhere, i.e., they are parallel. So, we have seen sever ...

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES 45 point (4, 2) lies on the lines represented by both the equations x – 2y = 0 and 3 x ...

46 MATHEMATICS (i) the lines may intersect in a single point. In this case, the pair of equations has a unique solution (consist ...

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES 47 Fig. 3.5 are (i) intersecting, then^11 22 ab ab ✁ (ii)coincident, then^111 222 abc ...

48 MATHEMATICS Example 5 : Graphically, find whether the following pair of equations has no solution, unique solution or infinit ...

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES 49 Plot the points and draw the lines passing through them to represent the equations, ...

50 MATHEMATICS (i) x + y = 5, 2 x + 2y = 10 (ii) x – y = 8, 3 x – 3y = 16 (iii) 2x + y – 6 = 0, 4 x – 2y – 4 = 0 (iv) 2x – 2y – ...

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES 51 Step 2 : Substitute the value of x in Equation (1). We get 7(3 – 2y) – 15y =2 i.e., ...

52 MATHEMATICS Using Equation (2), we get s = 3t + 6. Putting this value of s in Equation (1), we get (3t + 6) – 7t + 42 = 0, i. ...

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES 53 Solution : The pair of linear equations formed were: x + 2y – 4 = 0 (1) 2 x + 4y – ...

54 MATHEMATICS (iv) The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For ...

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES 55 So, the solution of the equations is x = 2000, y = 4000. Therefore, the monthly inc ...