7.3 Analysis of Statically Indeterminate Structures 231while the multiplication of the summary unit bending moment diagramMN†by a
bending moment diagramMP^0 due to applied load in the primary structureMN†MP^0
EID1
1 EI5
6
18 57 C 13 32 C 4 38:2513 C 18
21
2 EI4
6.2 10 C6/ 32 D3;455:25
EI:Therefore, the coefficients and free termsof equations (a) are computed correctly.
4.Primary unknowns.Canonical equations for primary unknownsX 1 andX 2
becomes
666:67X 1 C275X 2 2;294D0;
275X 1 C170:67X 2 1;161:25D0: (d)All coefficients and free terms contain factor 1/EI, which can be cancelled. It
means that primary unknowns of the force method depend only onrelativestiff-
nesses of the elements.
The solution of these two equations leads toX 1 D1:8915kN;X 2 D3:7562kN:5.Internal force diagrams.The bending moment diagram of the structure will be
readily obtained using the expression
MDMN 1 X 1 CMN 2 X 2 CMP^0 : (e)Location of the specified points 1–8 is shown in Fig.7.11b. Corresponding calcula-
tion is presented in Table7.4. The sign of bending moments is chosen arbitrarily for
summation purposes only.Ta b l e 7. 4 Calculation of bending moments at the specified points
Points MN 1 MN 1 X 1 MN 2 MN 2 X 2 MP^0 M
1 10 18.915 8.0 30.049 C57.0 C8.036
2 ^10 18.915 5.5 20.659 C38.25 1.324
3 10 18.915 3.0 11.268 C32.0 C1.817
4 0.0 0.0 3.0 11.268 C32.0 11.268
5 0.0 0.0 0.0 0.0 0.0 0.0
6 10 18.915 0.0 0.0 C32.0 C13.085
7 6.0 11.349 0.0 0.0 0.0 11.349
8 0.0 0.0 0.0 0.0 0.0 0.0signs of
bending moments
+ −+
−The resulting bending moment diagram and corresponding elastic curve are pre-
sented in Fig.7.11g.