252 14 · SPEED OF CHEMICAL REACTIONS
Examples of rate expressions found by
experiment
Decomposition of ethanal
Ethanal (CH 3 CHO) molecules may be broken up by heating:
CH 3 CHO(g)CH 4 (g)CO(g)
Experiments show the rate expression to be
rate of reaction k[CH 3 CHO]1.5
14.4
BOX 14.2
Dependence of the rate constant kupon temperature: the
Arrhenius equation
Experiments show that the way that the rate
constantfor a chemical reaction varies with
temperature can be described by the
Arrhenius equation:
kAeE/RT
wherekis the rate constant at temperature T
(K),Ais a constant for the reaction, Ris the
gas constant (8.3145 J mol^1 K^1 ) and E(in
J mol^1 ) is the so-called Arrhenius activation
energyfor the reaction. The Arrhenius
equation is useful because it is found to apply
even if the reaction under study does not
occur in one simple step.
Taking natural logs (ln) to both sides of the
Arrhenius equation gives an equation of the
form
ymxc
thus
lnklnA(E)^1
RT
If we have measured the rate constants for a
named reaction at various temperatures, we
can plot ln kagainst 1/T, giving a straight line
graph of slope E/R. This is the way that
Arrhenius activation energies are calculated
from experimental data.
The Arrhenius activation energy Eisnotthe
same as the reaction activation energy EA
(which is only meaningful for single-step
reactions). It is better to look upon the
Arrhenius activation energy simply as a useful
experimental index which shows how quickly
the rate constant of a reaction changes as
the temperature is changed:
●IfE0, the rate constant is independent
of temperature.
●IfEis small, the rate constant has only a
slight dependence upon temperature (Fig.
14.4(c)).
●IfEis large, the rate constant changes
dramatically with changes in temperature
(Fig. 14.4(a)).
If the rate constant of a reaction is k 1 at
temperatureT 1 , and k 2 at temperature T 2 , the
Arrhenius equations for both temperatures
may be combined to give the expression
k 1 E 1 1
ln(—)—(——)
k 2 R T 2 T 1
Provided that we know the Arrhenius
activation energy for the reaction, this
equation may be used to calculate the rate
constant at one temperature, knowing the
rate constant at another temperature. For
example, if for a particular chemical reaction,
k 1 1.0 10 ^3 mol^1 dm^3 s^1 at 300 K
and
E50 kJ mol^1 (i.e. 50 000 J mol^1 ),
then, at 320 K,
ln^10 ^3 50 000^11
(——k 2 )———8.3145 320(———— 300 )1.25
or
(
10 ^3
)e
1.250.287
k 2
so that k 2 10 ^3 /0.287 3.5
10 ^3 mol^1 dm^3 s^1. In other words, the rate
constant has increased by a factor of 3.5 for
an increase in temperature of only 20 K.