Handbook of Civil Engineering Calculations

tion for V 1 , ft (m); F 1 and V 2 = vertical she'ar at critical section for stresses V 1 and V 2 , re- spectively. In accordanc ...

67.9 kips (302.02 kN); V 2 = V 2 I(Ld) = 67,900/[92(19.S)] = 38 lb/in 2 (262.0 kPa) < 60 lb/in^2 (413.7 kPa). This is accepta ...

(c) Bending-moment diagram FIGURE 26 cause the required footing would project beyond the property limits. It then becomes nec- e ...

FIGURE 27 her thus functions as a beam that overhangs one support. However, since the footing is considerably wider than the col ...

Compute the vertical shear at distance d from the column face Establish the width of the footing. Thus V= 229.2 - 2.63(30.1) - ...

prises a vertical stem to retain the soil, a horizontal base to support the stem, and in many instances a key that projects into ...

ance to sliding. The sides of the key are sloped to ensure that the surrounding soil will re- main undisturbed during excavation ...

Design the stem At the base of the stem, y = 16.5 ft (5.03 m) and d = 18 - 3.5 = 14.5 in (368.30 mm); TEF = 7030 Ib (31,269.4 N ...

FIGURE 30 following calculations demonstrate, the theoretical cutoff point lies at y = 11 ft 7 in (3.531 m), where M = 218,400 i ...

Case 2: surcharge extending to H—p = 2370 + 500 = 2870 lb/ft^2 (137.4 kPa); V = 6.5[2870 - !/2(2474 + 828)] = 7920 Ib (35,228.1 ...

the lateral restraint, the tendons are deformed to a wedge shape across a relatively short distance at each end of the member. I ...

inclines downward to the right. A load is positive if it acts downward. The vertical shear at a given section is positive if the ...

is in equilibrium, the left portion also induces compressive stresses on the concrete at C, these stresses having a resultant th ...

Calculation Procedures: Compute the beam properties Thus, A = 12(18) = 216 in^2 (1393.6 cm^2 ); Sb = St = (Y 6 )(^)(IS)^2 = 648 ...

The offset from a reference line through B to the arc BD represents the value offbw at that section. Construct the final-stress ...

FIGURE 33. Stresses in bottom fiber along half-span. This procedure illustrates the following principles relevant to a beam with ...

Compute the stresses at midspan due to the beam weight Thus, Mw = (^1 / 8 )(83)(20)^2 (12) = 49,800 in-lb (5626.4 N-m); fbw = - ...

Verify the value of F 1 min by checking the critical stresses At support:/^- - + 2338 lb/in^2 (16,120.5 kPa);^ =-190 lb/in^2 (- ...

Calculation Procedure: Compute the beam-weight stresses at B In the composite stress diagram, Fig. 35Z?, the difference between ...

parabolic in the present case. Therefore, it is possible to achieve the full allowable initial stresses at midspan. Thus,/w =fb ...