15.4 Derivation of the Hartree-Fock equations 505
15.4.2 Varying the single-particle wave functions
If we generalize the Euler-Lagrange equations to more variables and introduceN^2 Lagrange
multipliers which we denote byεμ ν, we can write the variational equation for the functional
of Eq. (15.23) as
δE−N
∑
μ= 1N
∑
ν= 1εμ νδ∫
ψμ∗ψν= 0. (15.23)For the orthogonal wave functionsψμthis reduces to
δE−N
∑
μ= 1εμδ∫
ψμ∗ψμ= 0. (15.24)Variation with respect to the single-particle wave functionsψμyields thenN
∑
μ= 1∫
δ ψμ∗hˆiψμdxi+^1
2N
∑
μ= 1N
∑
ν= 1[∫
δ ψ∗μψν∗^1
ri j
ψμψνd(xixj)−∫
δ ψμ∗ψν∗^1
ri j
ψνψμdridrj]
+
N
∑
μ= 1∫
ψμ∗hˆiδ ψμdri+1
2
N
∑
μ= 1N
∑
ν= 1[∫
ψ∗μψν∗1
ri j
δ ψμψνdridrj−∫
ψμ∗ψν∗1
ri j
ψνδ ψμdridrj]
−
N
∑
μ= 1Eμ∫
δ ψ∗μψμdxi−N
∑
μ= 1Eμ∫
ψμ∗δ ψμdri= 0.(15.25)Although the variationsδ ψandδ ψ∗are not independent, they may in fact be treated as
such, so that the terms dependent on eitherδ ψandδ ψ∗individually may be set equal to
zero. To see this, simply replace the arbitrary variationδ ψbyiδ ψ, so thatδ ψ∗is replaced by
−iδ ψ∗, and combine the two equations. We thus arrive at the Hartree-Fock equations
[
−
1
2
∇^2 i−Z
ri+
N
∑
ν= 1∫
ψν∗(rj)1
ri j
ψν(rj)drj]
ψμ(xi)−
[N
∑
ν= 1∫
ψν∗(rj)1
ri j
ψμ(rj)drj]
ψν(ri) =εμψμ(ri).(15.26)Notice that the integration∫
drjimplies an integration over the spatial coordinatesrjand
a summation over the spin-coordinate of electronj.
The two first terms are the one-body kinetic energy and the electron-nucleus potential.
The third ordirectterm is the averaged electronic repulsion of the other electrons. This
term includes the ’self-interaction’ of electrons wheni=j. The self-interaction is cancelled in
the fourth term, or theexchangeterm. The exchange term results from our inclusion of the
Pauli principle and the assumed determinantal form of the wave-function. The effect of the
exchange is for electrons of like-spin to avoid each other. Atheoretically convenient form of
the Hartree-Fock equation is to regard the direct and exchange operator defined through the
following operators
Vμd(ri) =∫
ψμ∗(rj)^1
ri j
ψμ(rj)drj (15.27)and
Vμex(ri)g(ri) =(∫
ψ∗μ(rj)1
ri jg(rj)drj)
ψμ(ri), (15.28)