Computational Chemistry

(Steven Felgate) #1
CH 3 NC to CH 3 CN
Transition state 0 K relative E¼ 173 Product 0 K relative E¼# 120
Ea¼DH{þRT¼DH{þ2.48¼174.0

O

107.2
107.2, sic

120.3120.3, sic

1.082
1.090
1.504
1.503

1.188
1.223

Cs

–153.22222 + 0.04951
= –153.17271, rel. E = 236 kJ


  • 153.22564 + 0.04983
    = – 153.17581, rel. E = 233 kJ mol–1


–153.34454 + 0.05474
= –153.28980, rel. E = –71.6 kJ


  • 153.34692 + 0.05507
    = –153.29185, rel. E = –71.7, sic kJ mol–1


–93.12310 + 0.01557


  • 93.12554 + 0.01520
    = – 93.11034, rel. E = 0 kJ mol–1


–93.06713 + 0.01061
= –93.05652, rel. E = 134 kJ


  • 93.06747 + 0.01063
    = – 93.05684, rel. E = 140 kJ mol–1


–93.15452 + 0.01643
= –93.13809, rel. E = -80.3 kJ


  • 93.15894 + 0.01540
    = – 93.14354, rel. E = – 87.2 kJ mol–1


–132.22339 + 0.04191
= –132.18148, rel. E = 168 kJ


  • 132.22493 + 0.04236


–132.29008 + 0.04450

–132.29289 + 0.04463

–132.33371 + 0.04466
= –132.28905, rel. E = –114 kJ


  • 132.33825 + 0.04445


579i
C
C C

1.386
1.406

96.1
92.2
41.8
43.6

1.380
1.389

2.057
2.014

42.144.2
C

C 1.478 C
1.482

1.4961.502

59.2
59.1
60.460.4 CCC

D2d

1.296
1.313

–116.12337 + 0.05303
= –116.07034, rel. E = 0 kJ mol–1


  • 116.12370 + 0.05321
    = – 116.07049, rel. E = 0 kJ mol–1


–116.11229 + 0.05246
= –116.05983, rel. E = 27.6 kJ


  • 116.11330 + 0.05260
    = –116.06070, rel. E = 25.7 kJ mol–1
    (rel. E = 70.3 kJ mol–1)


O

H
Cs

117.7117.5
110.7
110.3

1.318
1.337

1.3471.369

0.9490.974HF geom
MP2 geom

N C
1.135
1.180
1.468
1.463

H O

C 1

112.6114.0 1.420
1.406 119.2118.4

1.252
1.295

1.2931.234
1.519
1.521

2574 i HF freq
2345i MP2 freq

1227 i
1310i
H N C
1.0020.9851.1541.187

Civ

C3v

C2v

C3v

Cs Civ

Cs

C 1

H
N

1.455
1.409

1.155
1.177
50.8
53.0

77.5
72.8

N C H
1.1331.177 1.0591.069

N C
1.422
1.426
1.153
1.189
NC

C
64.2
65.9 75.875.3
1.174
1.206

1.8581.896 1.742
1.753

468 i
444i

–116.23306 + 0.05430
= –116.17876, rel. E = –285 kJ


  • 116.23413 + 0.05393
    = –116.18020, rel. E = – 288 kJ mol–1


HF optimization

–153.31831 + 0.05578
= –153.26253, rel. E = 0 kJ mol–1


  • 153.32005 + 0.05546
    = – 153.26459, rel. E = 0 kJ mol–1


MP2 single point on HF geom

MP2 optimization

C

548 i

(rel. E = 0 kJ mol–1) (rel. E = 294 kJ mol–1) (rel. E = –73.8 kJ mol–1)

(rel. E = 0 kJ mol–1) (rel. E = 153 kJ mol–1) (rel. E = –50.4 kJ mol–1)

(rel. E = 0 kJ mol–1) (rel. E = 184 kJ mol–1) (rel. E = –86.7 kJ mol–1)
= – 132.18257, rel. E = 173 kJ mol–1 =^ – 132.29380, rel. E =^ – 120 kJ mol–1

= –132.24558, rel. E = 0 kJ mol–1
= – 132.24826, rel. E = 0 kJ mol–1

= –93.10753, rel. E = 0 kJ mol–1

(rel. E = 0 kJ mol–1) (rel. E = –243 kJ mol–1)

Fig. 5.21 Calculated geometries and energies for four reactions (most H’s are omitted, for
clarity). The purpose of the figure is the compare the single-point energies with energies from
optimization at a higher level. Geometries are HF/6–31G and MP2/6–31G. Energies are MP2/
6–31G//HF/6–31G (i.e. single-point) with HF ZPE, MP2/6–31G//MP2//6–31G with MP2/
6–31G ZPE, and (only relative energies shown,in parentheses) HF/6–31G//HF/6–31G* with
HF ZPE. Ab initioE(hartrees)þZPE (hartrees)¼corrected ab initioE; relativeE(strictly
speaking, 0 K enthalpy differences):Edifference in hartrees' 2626 ¼kJ mol#^1 ). The ZPEs
shown are the ab initio ZPEs multiplied by 0.9135 (HF) or 0.967 (MP2) [ 80 ]. For a discussion of
experimental measurements on these reactions, see [ 92 ]; available experimental activation and
reaction energies (kJ mol#^1 ) are shown here. Calculations here are by the author


268 5 Ab initio Calculations

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