11.2 Hofstetter’s compass-only construction of the golden section 323
11.2 Hofstetter’s compass-only construction of the golden
section
Kurt Hofstetter has found the following construction of the golden sec-
tion by striking the compass only five times.^1
We denote byP(Q)the circle withPas center andPQas radius.
Figure 1 shows two circlesA(B)andB(A)intersecting atC andD.
The lineABintersects the circles again atEandF. The circlesA(F)
andB(E)intersect at two pointsXandY. It is clear thatC,D,X,
Y are on a line. It is much more interesting to note thatDdivides the
segmentCXin the golden ratio,i.e.,
CD
CX
=
√
5 − 1
2
.
This is easy to verify. If we assumeABof length 2, thenCD=2
√
3
andCX=
√
15 +
√
3. From these,
CD
CX
=
2
√
3
√
15 +
√
3
=
2
√
5+1
=
√
5 − 1
2
.
X
D
C
E AFB
Y
X
D
C
E A B F
Y
This shows that to construct three collinear points in golden section,
we need four circles and one line. It is possible, however, to replace the
lineABby a circle, sayC(D). See Figure 2. Thus,the golden section
can be constructed with compass only, in 5 steps.
Here is a simple application: to divide a given segment into golden
section.^2
Construction 11.1.Given a segmentAB, construct
(^1) K. Hofstetter, A simple construction of the golden section,Forum Geometricorum, 2 (2002) 65–66.
(^2) Communicated by K. Hofstetter on December 9, 2003.