13-1210.023.03.04.05
.06
.07.08.1030 50 70 90 110 130 150 170 190
10 30 50 70 90 110 130 150 170 190λ(forα= 0.05)
λ(forα= 0.01)Probability of accepting the hypothesis.01.20.30.40.50
.60
.70
.801.00.02.03.04.05.06.07.08.10Probability of accepting the hypothesis.01.20.30.40.50.60.70.801.001 5 7 9 1113151719212325
1 3 5 7 9 11 13 15 17 19 21 23 25λ(forα= 0.05)
λ(forα= 0.01)7
860210
8202∞6 =ν
2 = 6 10
20
∞νν 1 = 1α= .01
α= .056 =10
12
15
20
30
∞νν 1 = 2α= .05α= .01Source: Reproduced with permission from Engineering Statistics,2nd edition, by A. H. Bowker and G. J.
Lieberman, Prentice-Hall, Englewood Cliffs, N.J., 1972.PQ220 6234F.Ch 13_CD 5/8/02 7:54 PM Page 12 RK UL 6 RK UL 6:Desktop Folder:TEMP WORK:PQ220 MONT 8/5/2002:Ch 13: