Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

102 Higher Engineering Mathematics


(a) cot 17. 49 ◦=

1
tan17. 49 ◦

=3.1735

(b) cot 163◦ 52 ′=

1
tan163◦ 52 ′

=

1

tan163

52 ◦
60
=−3.4570

Problem 12. Evaluate, correct to 4 significant
figures:
(a) sin1.481 (b) cos( 3 π/ 5 ) (c) tan2. 93

(a) sin1.481 means the sine of 1.481radians. Hence
a calculator needs to be on the radian function.
Hence sin1. 481 =0.9960
(b) cos( 3 π/ 5 )=cos1. 884955 ···=−0.3090
(c) tan2. 93 =−0.2148

Problem 13. Evaluate, correct to 4 decimal
places:
(a) secant 5.37 (b) cosecantπ/ 4
(c) cotangentπ/ 24

(a) Again, with no degrees sign, it is assumed that
5.37 means 5.37radians.
Hence sec5. 37 =

1
cos 5. 37

=1.6361

(b) cosec(π/ 4 )=

1
sin(π/ 4 )

=

1
sin0. 785398 ...
=1.4142

(c) cot( 5 π/ 24 )=

1
tan( 5 π/ 24 )

=

1
tan0. 654498 ...
=1.3032

Problem 14. Find, in degrees, the acute angle
sin−^10 .4128 correct to 2 decimal places.

sin−^10 .4128 means ‘the angle whose
sine is 0.4128’
Using a calculator:


  1. Press shift 2. Press sin 3. Enter 0.4128

  2. Press ) 5. Press=The answer 24.380848......
    is displayed


Hence, sin−^10. 4128 = 24. 38 ◦

Problem 15. Find the acute angle cos−^10 .2437 in
degrees and minutes

cos−^10 .2437 means ‘the angle whose
cosine is 0.2437’

Using a calculator:


  1. Press shift 2. Press cos 3. Enter 0.2437

  2. Press ) 5. Press=The answer 75.894979...
    is displayed

  3. Press◦”’ and 75◦ 53 ′ 41. 93 ′′is displayed


Hence, cos−^10. 2437 = 75. 89 ◦= 77 ◦ 54 ′
correct to the nearest minute.

Problem 16. Find the acute angle tan−^17 .4523 in
degrees and minutes

tan−^17 .4523 means ‘the angle whose
tangent is 7.4523’

Using a calculator:


  1. Press shift 2. Press tan 3. Enter 7.4523

  2. Press ) 5. Press =The answer 82.357318...
    is displayed

  3. Press◦”’ and 82◦ 21 ′ 26. 35 ′′is displayed


Hence, tan−^17. 4523 = 82. 36 ◦= 82 ◦ 21 ′
correct to the nearest minute.

Problem 17. Determine the acute angles:
(a) sec−^12 .3164 (b) cosec−^11. 1784
(c) cot−^12. 1273

(a) sec−^12. 3164 =cos−^1

(
1
2. 3164

)

=cos−^10. 4317 ...
=64.42◦or 64 ◦ 25 ′
or1.124radians

(b) cosec−^11. 1784 =sin−^1

(
1
1. 1784

)

=sin−^10. 8486 ...
=58.06◦or 58 ◦ 4 ′
or1.013radians
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