Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

164 Higher Engineering Mathematics


tan

(
x+

π
4

)
=

tanx+tanπ 4
1 −tanxtanπ 4
from the formula fortan(A+B)

=

tanx+ 1
1 −(tanx)( 1 )

=

(
1 +tanx
1 −tanx

)

since tan

π
4

= 1

tan

(
x−

π
4

)
=

tanx−tanπ 4
1 +tanxtanπ 4

=

(
tanx− 1
1 +tanx

)

Hence tan

(
x+

π
4

)
tan

(
x−

π
4

)

=

(
1 +tanx
1 −tanx

)(
tanx− 1
1 +tanx

)

=

tanx− 1
1 −tanx

=

−( 1 −tanx)
1 −tanx

=− 1

Problem 4. If sinP= 0 .8142 and cosQ= 0. 4432
evaluate, correct to 3 decimal places:
(a) sin(P−Q),(b)cos(P+Q)and
(c) tan(P+Q), using the compound-angle
formulae.

Since sinP= 0 .8142 then
P=sin−^10. 8142 = 54. 51 ◦.
Thus cosP=cos54. 51 ◦= 0 .5806 and
tanP=tan54. 51 ◦= 1. 4025
Since cosQ= 0 .4432,Q=cos−^10. 4432 = 63. 69 ◦.
Thus sinQ=sin63. 69 ◦= 0 .8964 and
tanQ=tan63. 69 ◦= 2. 0225
(a) sin(P−Q)
=sinPcosQ−cosPsinQ
=( 0. 8142 )( 0. 4432 )−( 0. 5806 )( 0. 8964 )
= 0. 3609 − 0. 5204 =− 0. 160

(b) cos(P+Q)
=cosPcosQ−sinPsinQ
=( 0. 5806 )( 0. 4432 )−( 0. 8142 )( 0. 8964 )
= 0. 2573 − 0. 7298 =− 0. 473

(c) tan(P+Q)

=

tanP+tanQ
1 −tanPtanQ

=

( 1. 4025 )+( 2. 0225 )
1 −( 1. 4025 )( 2. 0225 )

=

3. 4250
− 1. 8366

=− 1. 865

Problem 5. Solve the equation

4sin(x− 20 ◦)=5cosx

for values ofxbetween 0◦and 90◦.

4sin(x− 20 ◦)=4[sinxcos20◦−cosxsin20◦],
from the formula forsin(A−B)
=4[sinx( 0. 9397 )−cosx( 0. 3420 )]
= 3 .7588sinx− 1 .3680cosx

Since 4sin(x− 20 ◦)=5cosxthen
3 .7588sinx− 1 .3680cosx=5cosx
Rearranging gives:

3 .7588sinx=5cosx+ 1 .3680cosx
= 6 .3680cosx

and
sinx
cosx

=
6. 3680
3. 7588

= 1. 6942

i.e. tanx= 1 .6942, andx=tan−^11. 6942 = 59. 449 ◦or
59 ◦ 27 ′

[Check: LHS=4sin( 59. 449 ◦− 20 ◦)

=4sin39. 449 ◦= 2. 542

RHS=5cosx=5cos59. 449 ◦= 2 .542]

Now try the following exercise

Exercise 72 Further problems on
compound angle formulae


  1. Reduce the following to the sine of one
    angle:
    (a) sin37◦cos21◦+cos37◦sin21◦
    (b) sin7tcos3t−cos 7tsin3t
    [(a) sin58◦(b) sin4t]

  2. Reduce the following to the cosine of one
    angle:
    (a) cos71◦cos33◦−sin71◦sin33◦


(b) cos

π
3

cos

π
4

+sin

π
3

sin

π
4


(a)cos104◦≡−cos76◦

(b)cos

π
12


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