Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

170 Higher Engineering Mathematics


LHS=

1 −cos2θ
sin2θ

=

1 −( 1 −2sin^2 θ)
2sinθcosθ

=

2sin^2 θ
2sinθcosθ

=

sinθ
cosθ
=tanθ=RHS

Problem 13. Prove that
cot 2x+cosec 2x=cotx.

LHS=cot2x+cosec 2x=

cos2x
sin2x

+

1
sin2x

=
cos2x+ 1
sin2x

=

(2cos^2 x− 1 )+ 1
sin2x

=

2cos^2 x
sin2x

=

2cos^2 x
2sinxcosx
=

cosx
sinx

=cotx=RHS

Problem 14. Solve the equation
cos2θ+3sinθ=2forθin the range 0◦≤θ≤ 360 ◦.

Replacing the double angle term with the relationship
cos2θ= 1 −2sin^2 θgives:
1 −2sin^2 θ+3sinθ= 2

Rearranging gives: −2sin^2 θ+3sinθ− 1 = 0
or 2sin^2 θ−3sinθ+ 1 = 0
which is a quadratic in sinθ
Using the quadratic formula or by factorising gives:
(2sinθ− 1 )(sinθ− 1 )= 0
from which, 2sinθ− 1 =0orsinθ− 1 = 0
and sinθ=^12 or sinθ= 1
from which, θ= 30 ◦or 150◦or 90◦

Now try the following exercise

Exercise 74 Further problems on double
angles


  1. The powerpin an electrical circuit is given by


p=

v^2
R

. Determine the power in terms ofV,
Rand cos2twhenv=Vcos[t.
V^2
2 R


( 1 +cos2t)

]


  1. Prove the following identities:
    (a) 1−


cos2φ
cos^2 φ

=tan^2 φ

(b)

1 +cos2t
sin^2 t

=2cot^2 t

(c)

(tan2x)( 1 +tanx)
tanx

=

2
1 −tanx
(d) 2cosec2θcos2θ=cotθ−tanθ


  1. If the third harmonic of a waveform is given by
    V 3 cos3θ, express the third harmonic in terms
    of the first harmonic cosθ,whenV 3 =1.
    [cos3θ=4cos^3 θ−3cosθ]
    In Problems 4 to 8, solve for θ in the range
    − 180 ◦≤θ≤ 180 ◦

  2. cos2θ=sinθ [− 90 ◦, 30 ◦, 150 ◦]

  3. 3sin2θ+2cosθ= 0
    [− 160. 47 ◦,− 90 ◦,− 19. 47 ◦, 90 ◦]

  4. sin2θ+cosθ= 0
    [− 150 ◦,− 90 ◦,− 30 ◦, 90 ◦]

  5. cos2θ+2sinθ=−3[− 90 ◦]

  6. tanθ+cotθ=2[ 45 ◦,− 135 ◦]


17.4 Changing products of sines and


cosines into sums or differences


(i) sin(A+B)+sin(A−B)=2sinAcosB(fromthe
formulae in Section 17.1)

i.e. sinAcosB
=^12 [sin(A+B)+sin(A−B)] (1)

(ii) sin(A+B)−sin(A−B)=2cosAsinB

i.e. cosAsinB

=^12 [sin(A+B)−sin(A−B)] (2)

(iii) cos(A+B)+cos(A−B)=2cosAcosB

i.e. cosAcosB

=^12 [cos(A+B)+cos(A−B)] (3)
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