An introduction to partial differential equations 527
from which,X=Acospx+Bsinpx
and Y=Cepy+De−py
or Y=Ccoshpy+Dsinhpy
or Y=Esinhp(y+φ)
Hence u(x,y)=XY
={Acospx+Bsinpx}{Esinhp(y+φ)}
or u(x,y)
={Pcospx+Qsinpx}{sinhp(y+φ)}
whereP=AEandQ=BE.
The first boundary condition is: u( 0 ,y)= 0 , hence
0 =Psinhp(y+φ)from which,P=0.
Hence,u(x,y)=Qsinpxsinhp(y+φ).
The second boundary condition is:u( 1 ,y)= 0 ,hence
0 =Qsinp( 1 )sinhp(y+φ)from which,
sinp= 0 ,hence,p=nπ forn= 1 , 2 , 3 ,...
The third boundary condition is:u(x, 0 )= 0 ,hence,
0 =Qsinpxsinhp(φ)from which,
sinhp(φ)=0andφ=0.
Hence,u(x,y)=Qsinpxsinhpy.
Since there are many solutions for integer values ofn,
u(x,y)=
∑∞
n= 1
Qnsinpxsinhpy
=
∑∞
n= 1
Qnsinnπxsinhnπy (a)
The fourth boundary condition is:u(x, 1 )= 4 =f(x),
hence,f(x)=
∑∞
n= 1
Qnsinnπxsinhnπ( 1 ).
From Fourier series coefficients,
Qnsinhnπ= 2 ×the mean value of
f(x)sinnπxfromx=0tox= 1
i.e. =
2
1
∫ 1
0
4sinnπxdx
= 8
[
−
cosnπx
nπ
] 1
0
=−
8
nπ
(cosnπ−cos0)
=
8
nπ
( 1 −cosnπ)
= 0 (for even values ofn),
=
16
nπ
(for odd values ofn)
Hence, Qn=
16
nπ(sinhnπ)
=
16
nπ
cosechnπ
Hence, from equation (a),
u(x,y)=
∑∞
n= 1
Qnsinnπxsinhnπy
=
16
π
∑∞
n(odd)= 1
1
n
(cosechnπsinnπxsinhnπy)
Now try the following exercise
Exercise 203 Further problemson the
Laplace equation
- A rectangular plate is bounded by the
linesx= 0 ,y= 0 ,x=1andy= 3 .Apply the
Laplace equation
∂^2 u
∂x^2
+
∂^2 u
∂y^2
=0 to determine
thepotentialdistributionu(x,y)overtheplate,
subject to the following boundary conditions:
u=0whenx= 00 ≤y≤2,
u=0whenx= 10 ≤y≤ 2 ,
u=0wheny= 20 ≤x≤ 1 ,
u=5wheny= 30 ≤x≤1.
⎡
⎣u(x,y)=^20
π
∑∞
n(odd)= 1
1
n
cosechnπsinnπxsinhnπ(y− 2 )
⎤
⎦
- A rectangular plate is bounded by the
linesx= 0 ,y= 0 ,x= 3 ,y= 2 .Determine the
potential distributionu(x,y)over the rec-
tangle using the Laplace equation
∂^2 u
∂x^2
+
∂^2 u
∂y^2
=0, subject to the following
boundary conditions:
u( 0 ,y)= 00 ≤y≤2,
u( 3 ,y)= 00 ≤y≤2,
u(x, 2 )= 00 ≤x≤3,
u(x, 0 )=x( 3 −x) 0 ≤x≤3.
⎡
⎣u(x,y)=^216
π^3
∑∞
n(odd)= 1
1
n^3 cosech
2 nπ
3 sin
nπx
3 sinh
nπ
3 (^2 −y)
⎤
⎦