PHYSICAL CHEMISTRY IN BRIEF
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 181 Note:The wordotheris used here to emphasize that the conditions of phase equilibrium (e ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 182 7.4 Phase diagrams 7.4.1 General terms Phase diagramis a diagram allowing us to determ ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 183 s s TNFP TNBP T pst p T 1 T 2 (sβ) (sα) (l) (g) sC Obr.7.1:Phase diagramp−T of a one-co ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 184 Solution If the system shown in Figure7.1is kept under constant pressurepst, then for t ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 185 rqq (^0) x( 1 β) Z 1 x( 1 γ) 1 T 1 TH T ^ / (α) + (β) (α) + (γ) (α) (β) (γ) (β) + (γ) ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 186 Obr.7.3:Triangular diagram. 7.4.4 Phase diagrams of three-component (ternary) mixtures ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 187 Obr.7.4:Example of an isobaric-isothermal diagram of a three-component. system. The re ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 188 7.4.5 Material balance Let us have a system composed ofkcomponents andfcoexisting phase ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 189 of phases (γ) and (β) are in the ratio of the lengths of the line segmentsABandBC. n(γ) ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 190 7.5 Phase equilibria of pure substances For a pure component the intensive criterion of ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 191 is negligible compared to the volume of the gas. The equation is a good approximation w ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 192 Solution We use equation (7.16) into which we substitute the following values:T 1 = 272 ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 193 7.5.4 Solid-vapour equilibrium This subsection deals with the temperature-pressure depe ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 194 Solution We use equation (7.19) in which ∆fusV = 18× 10 −^6 − 19. 8 × 10 −^6 =− 1. 8 × ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 195 7.6 Liquid-vapour equilibrium in mixtures This section deals with the relations between ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 196 Specified Calculated From equation How T, x 1 p p=x 1 ps 1 +x 2 ps 2 analytically y 1 y ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 197 p p 1 p 2 ps 1 ps 2 p 0 x 1 1 Obr.7.5:Dependence of the total pressurepand partial pres ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 198 Obr.7.6:Isothermal diagram of a two-component system. The curves illustrate the depende ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 199 Figure7.6 presents a system with positive deviations from Raoult’s law. The lower curve ...
CHAP. 7: PHASE EQUILIBRIA [CONTENTS] 200 T Tb, 2 Tb, 1 s A (g) i (g)+(l) (l) 0 y 1 x 1 x′ 1 y 1 ′ 1 Obr.7.7:Isobaric diagram o ...
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