11.6
11.7
11.8
11.9
11.10
11.11
11.12
11.13
11.14 221 2222
x
Ne x
x x
αα
⎛ α
⎝
⎜⎜
⎞
⎠
⎟⎟
⎛
⎝
⎜⎜
⎞
⎠
− ⎟⎟
−∞
+∞
∫ ()()
/ (()Nex/ x
1
−^222 α d
()()()Ne 0 −xx^22 //^22 x Ne 0 222 x
−∞
+∞
−
∫
ααd
DO2Hμλ= ...λ 2 O
×
===
16 2
18
mmHH 178 138 4 11 μm
HO
HO /
DO
HO
2
16 1
17
094 2
2
μ ω^2
ω
μ
=.
×
mm==
k
HH kk/
μDO 2
178
094
138
.
.
=.
Peyey==//yy
∞
−−
∞
∫∫
11
12
1
12
1
22
απ
α
π
dd
ν
ν
2 21
2
m
m
km
km
==
/
/
A== −
ν
c
1087 cm^1
ν
πμ π.
==.
×
=
−
−
1
2
1
2
500
119 10
326
1
26
k Nm
kg
× 1013 s−^1
μ=.
+
=
×
+
=×
mm
mm
CO m
CO
p
13 16
13 16
119 10 0 −^26 kg
A== −
ν
c
1111 cm^1
ν
πμ π.
==.
×
=
−
−
1
2
1
2
500
114 10
333
1
26
k Nm
kg
× 1013 s−^1
μ=.
+
=
×
+
=×
mm
mm
CO m
CO
p
12 16
12 16
114 10−^26 kg
ν
π.
=.
×
=×
−
−
(^1) −
2
600
167 10
95 10
1
27
Nm 13
kg
s^11
μ=.
+
=
×
+
=×
mm
mm
CO m
CO
p
13 16
13 16
119 10−^26 kg
ANSWERS TO PROBLEMS 463
9781405124362_5_end.qxd 4/29/08 9:17 Page 463