Determinants and Their Applications in Mathematical Physics

(Chris Devlin) #1
5.1 Determinants Which Represent Particular Polynomials 171

b.ψn(x)=


1

n!

∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣

α 0 α 1 α 2 α 3 ··· αn− 1 αn

nx

n− 12 x

n− 23 x

.....................

1 nx

∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣

n+1

.

Both determinants are Hessenbergians (Section 4.6).


Proof of (a).Denote the determinant byHn+1, expand it by the two


elements in the last row, and repeat this operation on the determinants of


lower order which appear. The result is


Hn+1(x)=

n

r=1

(

n

r

)

Hn+1−r(−x)

r
+(−1)

n
αn.

TheHn+1term can be absorbed into the sum, giving


(−1)

n
αn=

n

r=0

(

n

r

)

Hn+1−r(−x)

r
.

This is an Appell polynomial whose inverse relation is


Hn+1(x)=

n

r=0

(

n

r

)

(−1)

n−r
αn−rx

r
,

which is equivalent to the stated result.


Proof of (b).Denote the determinant byH


n+1
and note that some

of its elements are functions ofn, so that the minor obtained by removing


its last row and column isnotequal toH



nand hence there is no obvious

recurrence relation linkingH



n+1,H


n,H


n− 1 , etc.

The determinantH


n+1can be obtained by transformingHn+1by a series

of row operations which reduce some of its elements to zero. MultiplyRi


by (n+2−i), 2≤i≤n+ 1, and compensate for the unwanted factorn!by


dividing the determinant by that factor. Now perform the row operations


R


i=Ri−

(

i− 1

n+1−i

)

xRi+1

first with 2≤i≤n, which introduces (n−1) zero elements intoCn+1,


then with 2≤i≤n−1, which introduces (n−2) zero elements intoCn,


then with 2≤i≤n−2, etc., and, finally, withi= 2. The determinant


H

n+1
appears. 

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