5.1 Determinants Which Represent Particular Polynomials 175
But
a
′
ij
+ai− 1 ,j=
[(
j− 1
i− 1
)
+
(
j− 1
i− 2
)]
u
(j−i+1)
−
[(
j− 1
i− 2
)
+
(
j− 1
i− 3
)]
v
(j−i+2)
=
(
j
i− 1
)
u
(j−i+1)
−
(
j
i− 2
)
v
(j−i+2)
=ai,j+1. (5.1.13)
Hence,
C
′
j+C
∗
j=Cj+1, (5.1.14)
A
′
n=
n
∑
j=1
∣
∣
C 1 C 2 ···C
′
jCj+1···Cn−^1 Cn
∣
∣
n
,
A
(n+1)
n+1,n
=−
∣
∣C
1 C 2 ···CjCj+1···Cn− 1 Cn+1
∣
∣
n
. (5.1.15)
Hence,
A
′
n+A
(n+1)
n+1,n
=
n
∑
j=1
∣
∣
C 1 C 2 ···(C
′
j−Cj+1)Cj+1···Cn
∣
∣
n
=−
n
∑
j=1
∣
∣C
1 C 2 ···C
∗
j
···Cn
∣
∣
=0
by Theorem 3.1 on cyclic dislocations and generalizations in Section 3.1,
which proves (a).
ExpandingAn+1by the two elements in its last row,
An+1=(u−nv
′
)An−vA
(n+1)
n+1,n
=(u−nv
′
)An+vA
′
n
=v
[
A
′
n
+
(
u
v
−
nv
′
v
)
An
]
,
yAn+1
v
n+1
=
y
v
n
[
A
′
n
+
(
y
′
y
−
nv
′
v
)
An
]
=
yA
′
n
v
n
+
(
y
v
n
)′
An
=D
(
yAn
v
n
)
=D
2
(
yAn− 1
v
n− 1
)
=D
r
(
yAn−r+1
v
n−r+1
)
, 0 ≤r≤n