Determinants and Their Applications in Mathematical Physics

(Chris Devlin) #1

182 5. Further Determinant Theory


LetH

n− 1
andK

n− 1
denote the determinants obtained fromHn− 1 and

Kn− 1 , respectively, by again replacing eachφrby (φr−xφr+1) and by


replacing eachψrby (ψr−xψr+1). In the notation of the second and


fourth lines of (5.2.6),


H


n− 1 =


∣φ
m−xφm+1



n

, 1 ≤m≤ 2 n− 3 ,

K


n− 1

=


∣ψ
m−xψm+1



n

, 1 ≤m≤ 2 n− 3. (5.2.18)

Lemma 5.4.


a.

n

i=1

H

(n)
in
x

n−i
=H


n− 1

,

b.


n

i=1

K

(n)
in
x

n−i
=K


n− 1

.

Proof of (a).


n

i=1

H

(n)
in
x

n−i
=

∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣

φ 1 φ 2 ··· φn− 1 x

n− 1

φ 2 φ 3 ··· φn x

n− 2

...............................

φn− 1 φn ··· φ 2 n− 3 x

φn φn+1 ··· φ 2 n− 2 1

∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ n

.

The result follows by eliminating thex’s from the last column by means of


the row operations:


R


i
=Ri−xRi+1, 1 ≤i≤n− 1.

Part (b) is proved in a similar manner. 

Lemma 5.5.


(−1)

i+1
Pf

(n)
i

=

∑n

j=1

H

(n)
jn

K

(n)
i−j+1,n
, 1 ≤i≤ 2 n− 1.

SinceK


(n)
mn=0whenm<^1 and whenm>n, the true upper limit in the

sum isi, but it is convenient to retainnin order to simplify the analysis


involved in its application.


Proof. It follows from the inductive assumption (5.2.10) that


Pf


n− 1 =H


n− 1 K


n− 1. (5.2.19)

Hence, applying Lemmas 5.3 and 5.4,


2 n− 1

i=1

(−1)

i+1
Pf

(n)
i x

2 n−i− 1
=

[

n

i=1

H

(n)
inx

n−i

][

n

s=1

K

(n)
snx

n−s

]

=



n

j=1

n

s=1

H

(n)
jnK

(n)
snx

2 n−j−s



[

s=i−j+1

s→i

]
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