222 5. Further Determinant Theory
Applying Taylor’s theorem again,1
2{φ(x+z)−φ(x−z)}=∞
∑n=0z
2 n+1
D
2 n+1
(φ)(2n+ 1)!,
1
2{ψ(x+z)+ψ(x−z)}=∞
∑n=0z2 n
D2 n
(ψ)(2n)!. (5.7.2)
5.7.2 A Determinantal Identity...............
Define functionsφ,ψ,unand a HessenbergianEnas follows:
φ= log(fg),ψ= log(f/g) (5.7.3)u 2 n=D2 n
(φ),u 2 n+1=D2 n+1
(ψ), (5.7.4)En=|eij|n,where
eij=
(
j− 1i− 1)
uj−i+1,j≥i,− 1 ,j=i−1,0 , otherwise.(5.7.5)
It follows from (5.7.3) that
f=e(φ+ψ)/ 2
,g=e(φ−ψ)/ 2
,fg=eφ. (5.7.6)
Theorem.
H
n
(f, g)fg=En=
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣
u 1 u 2 u 3 u 4 ··· un− 1 un− 1 u 1 2 u 2 3 u 3 ··· ···(
n− 1n− 2)
un− 1− 1 u 1 3 u 2 ··· ···(
n− 1n− 3)
un− 2− 1 u 1 ··· ··· ······ ··· ···− 1 u 1∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ n.
This identity was conjectured by one of the authors and proved by Cau-drey in 1984. The correspondence was private. Two proofs are given below.
The first is essentially Caudrey’s but with additional detail.