222 5. Further Determinant Theory
Applying Taylor’s theorem again,
1
2
{φ(x+z)−φ(x−z)}=
∞
∑
n=0
z
2 n+1
D
2 n+1
(φ)
(2n+ 1)!
,
1
2
{ψ(x+z)+ψ(x−z)}=
∞
∑
n=0
z
2 n
D
2 n
(ψ)
(2n)!
. (5.7.2)
5.7.2 A Determinantal Identity...............
Define functionsφ,ψ,unand a HessenbergianEnas follows:
φ= log(fg),
ψ= log(f/g) (5.7.3)
u 2 n=D
2 n
(φ),
u 2 n+1=D
2 n+1
(ψ), (5.7.4)
En=|eij|n,
where
eij=
(
j− 1
i− 1
)
uj−i+1,j≥i,
− 1 ,j=i−1,
0 , otherwise.
(5.7.5)
It follows from (5.7.3) that
f=e
(φ+ψ)/ 2
,
g=e
(φ−ψ)/ 2
,
fg=e
φ
. (5.7.6)
Theorem.
H
n
(f, g)
fg
=En
=
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣
u 1 u 2 u 3 u 4 ··· un− 1 un
− 1 u 1 2 u 2 3 u 3 ··· ···
(
n− 1
n− 2
)
un− 1
− 1 u 1 3 u 2 ··· ···
(
n− 1
n− 3
)
un− 2
− 1 u 1 ··· ··· ···
··· ··· ···
− 1 u 1
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ n
.
This identity was conjectured by one of the authors and proved by Cau-
drey in 1984. The correspondence was private. Two proofs are given below.
The first is essentially Caudrey’s but with additional detail.