4.1 Alternants 59
Wn=(−1)
n(n+1)/ 2
XnYn
n
∏
i=1
(xi+ 1)(yi−1).
Removingf(x 1 ),f(x 2 ),...,f(xn), from the firstnrows inVnandWn,
and expanding each determinant by the last row and column, deduce
that
∣
∣
∣
∣
1 −xiyj
xi−yj
∣
∣
∣
∣
n
=
1
2
∣
∣
∣
∣
1
xi−yj
∣
∣
∣
∣
n
{
n
∏
i=1
(xi+ 1)(yi−1)
+
n
∏
i=1
(xi−1)(yi+1)
}
4.1.6 A Determinant Related to a Vandermondian
LetPr(x) be a polynomial defined as
Pr(x)=
r
∑
s=1
asrx
s− 1
,r≥ 1.
Note that the coefficient isasr, not the usualars.
Let
Xn=|x
i− 1
j
|n.
Theorem.
|Pi(xj)|n=(a 11 a 22 ···ann)Xn.
Proof. Define an upper triangular determinantUnas follows:
Un=|aij|n,aij=0, i>j,
=a 11 a 22 ···ann. (4.1.7)
Some of the cofactors ofUiare given by
U
(i)
ij
=
{
0 ,j>i,
Ui− 1 ,j=i,U 0 =1.
Those cofactors for whichj<iare not required in the analysis which
follows. Hence,|U
(i)
ij
|nis also upper triangular and
|U
(i)
ij
|n=
{
U
(1)
11 U
(2)
22 ···U
(n)
nn,U
(1)
11 =1,
U 1 U 2 ···Un− 1.
(4.1.8)
Applying the formula for the product of two determinants in Section 1.4,
|U
(j)
ij
|n|Pi(xj)|n=|qij|n, (4.1.9)