550 CHAPTER 19 Structural Idealization
Eq.(19.11)reducestoqs=−Sy
Ixx∑nr= 1Bryr+qs,0 (i)inwhich
Ixx= 2 ( 200 × 302 + 250 × 1002 + 400 × 1002 + 100 × 502 )=13.86× 106 mm^4Equation(i)thenbecomes
qs=−10 × 103
13.86× 106
∑nr= 1Bryr+qs,0thatis,
qs=−7.22× 10 −^4∑nr= 1Bryr+qs,0 (ii)“Cutting”thebeamsectioninthewall23(anywallmaybechosen)andcalculatingthe“basic”shear
flowdistributionqbfromthefirsttermontheright-handsideofEq.(ii),wehave
qb,23= 0
qb,34=−7.22× 10 −^4 ( 400 × 100 )=−28.9N/mmqb,45=−28.9−7.22× 10 −^4 ( 100 × 50 )=−32.5N/mm
qb,56=qb,34=−28.9N/mm(bysymmetry)
qb,67=qb,23=0(bysymmetry)qb,21=−7.22× 10 −^4 ( 250 × 100 )=−18.1N/mm
qb,18=−18.1−7.22× 10 −^4 ( 200 × 30 )=−22.4N/mm
qb,87=qb,21=−18.1N/mm(bysymmetry)Takingmomentsabouttheintersectionofthelineofactionoftheshearloadandthehorizontalaxisof
symmetryandreferringtotheresultsofEqs.(19.7)and(19.8),wehave,fromEq.(16.18),
0 =[qb,81× 60 × 480 + 2 qb,12( 240 × 100 + 70 × 240 )+ 2 qb,23× 240 × 100
− 2 qb,43× 120 × 100 −qb,54× 100 ×120]+ 2 × 97200 qs,0Substitutingtheprecedingvaluesofqbinthisequationgives
qs,0=−5.4N/mmthenegativesignindicatingthatqs,0actsinaclockwisesense.