Engineering Mechanics

(^308) „„„„„ A Textbook of Engineering Mechanics Fig. 14.35. Example 14.14. A cantilever truss of span 2l is carrying loads as s ...

Chapter 14 : Analysis of Perfect Frames (Graphical Method) „„„„„ 309 Find the forces in all the members of a cantilever truss s ...

(^310) „„„„„ A Textbook of Engineering Mechanics Exmaple 14.15. Figure 14.39 shows a framed structure of 4 m span and 1.5 m heig ...

Chapter 14 : Analysis of Perfect Frames (Graphical Method) „„„„„ 311 Example 14.16. A truss of 8 m span and 4 m height is loaded ...

(^312) „„„„„ A Textbook of Engineering Mechanics Example 14.17. Figure 14.43 shows a pin-jointed frame carrying vertical loads o ...

Chapter 14 : Analysis of Perfect Frames (Graphical Method) „„„„„ 313 S.No. Member Magnitude of force in kN Nature of force 1 AB ...

(^314) „„„„„ A Textbook of Engineering Mechanics *Solution. Since the truss is supported on rollers at P, threfore the reaction ...

Chapter 14 : Analysis of Perfect Frames (Graphical Method) „„„„„ 315 Solution. Since the truss is supported on rollers at the ri ...

(^316) „„„„„ A Textbook of Engineering Mechanics Example 14.20. A truss hinged at A and supported on rollers at D is loaded as s ...

Chapter 14 : Analysis of Perfect Frames (Graphical Method) „„„„„ 317 14.10. FRAMES WITH BOTH ENDS FIXED Sometimes, a frame or a ...

(^318) „„„„„ A Textbook of Engineering Mechanics S.No. Member Magnitude of force in kN Nature of force 1 BF 2.9 Compression 2 FE ...

Chapter 14 : Analysis of Perfect Frames (Graphical Method) „„„„„ 319 Now, consider (for the time being only) the members OP and ...

(^320) „„„„„ A Textbook of Engineering Mechanics S. No. Member Magnitude of force in kN Nature of force 1 BL, IX 15,720 Compress ...

Chapter 14 : Analysis of Perfect Frames (Graphical Method) „„„„„ 321 Fig. 14.57 shows a truss pin-joint at one end, and freely ...

(^322) „„„„„ A Textbook of Engineering Mechanics 322 Equilibrium of Strings 15 CHAPTERCHAPTERCHAPTERCHAPTERCHAPTER 15.1.INTRODUC ...

Chapter 15 : Equilibrium of Strings „„„„„ 323 Fig. 15.1. Let w= Uniformly distributed load per unit length, l= Span of the cable ...

(^324) „„„„„ A Textbook of Engineering Mechanics well as levels of the two supports. Though there are many types of strings and ...

Chapter 15 : Equilibrium of Strings „„„„„ 325 Example 15.1. Three loads of 10 kN, 15 kN and 20 kN are suspended from a string AB ...

(^326) „„„„„ A Textbook of Engineering Mechanics Fig. 15.4. Now draw the vector diagram as shown in Fig. 15.4 (b) and as discuss ...

Chapter 15 : Equilibrium of Strings „„„„„ 327 ∴ 2 (^8) c wl H y We also know that the maximum tension in the cable will be at th ...