Engineering Mechanics

Chapter 5 : Equilibrium of Forces „„„„„ 69 Solving it as a quardrotic equation, 1.5 2.25 32 cos 0.9 or 25.8. 8 ++ θ= = θ= ° Ans ...

(^70) „„„„„ A Textbook of Engineering Mechanics Fig. 5.26. From the geometry of the triangle BDF, we find that 8 sin 0.4132 or 2 ...

Chapter 5 : Equilibrium of Forces „„„„„ 71 5.7. CONVERSE OF THE LAW* OF TRIANGLE OF FORCES If three forces acting at a point be ...

(^72) „„„„„ A Textbook of Engineering Mechanics Select some suitable point p and draw a vertical line pq equal to 15 N to some ...

Chapter 5 : Equilibrium of Forces „„„„„ 73 Now we shall study the above mentioned four states one by one. If the body moves in ...

(^74) „„„„„ A Textbook of Engineering Mechanics Stable equilibrium Fig. 5.30. A body is said to be in stable equilibrium, if i ...

Chapter 5 : Equilibrium of Forces „„„„„ 75 Solution. Given : Load at D (P) = 4 kN ; Load at E (W) = 2 kN; a = 3·0 m ; b = 0·9 m ...

(^76) „„„„„ A Textbook of Engineering Mechanics A ladle is lifted by means of three chains each 2 m in length. The upper ends o ...

Chapter 5 : Equilibrium of Forces „„„„„ 77 The Lami’s Theorem is applicable only for (a) Coplaner forces (b) Concurrent forces ...

(^78) „„„„„ A Textbook of Engineering Mechanics 78 Centre of Gravity 6 CHAPTERCHAPTERCHAPTERCHAPTERCHAPTER Contents Introductio ...

Chapter 6 : Centre of Gravity „„„„„ 79 through which the whole weight of the body acts, irrespect of its position, is known as c ...

(^80) „„„„„ A Textbook of Engineering Mechanics The centre of gravity of a semicircle is at a distance of 4 3 r π from its bas ...

Chapter 6 : Centre of Gravity „„„„„ 81 The centre of gravity of a segment of sphere of a height h is at a distance of 3(2 – )^ ...

(^82) „„„„„ A Textbook of Engineering Mechanics Let xand ybe the co-ordinates of the centre of gravity with respect to some axis ...

Chapter 6 : Centre of Gravity „„„„„ 83 Example 6.2. Find the centre of gravity of a channel section 100 mm × 50 mm × 15 mm. Solu ...

(^84) „„„„„ A Textbook of Engineering Mechanics (iii) Top flange a 3 = 150 × 50 = 7500 mm^2 and (^3) 50 100 300 425 mm 2 y =+ += ...

Chapter 6 : Centre of Gravity „„„„„ 85 Example 6.5. A uniform lamina shown in Fig. 6.14 consists of a rectangle, a circle and a ...

(^86) „„„„„ A Textbook of Engineering Mechanics Similarly, distance between centre of gravity of the section and bottom face of ...

Chapter 6 : Centre of Gravity „„„„„ 87 A figure consists of a rectangle having one of its sides twice the other, with an equila ...

(^88) „„„„„ A Textbook of Engineering Mechanics We know that distance between centre of gravity of the section and base of the c ...