Radius of moon = R
CA vA
h
R
100RB
Mass= MMoonvBSpeed of particle at B = vB
Escape velocity on
surface of moon = ve∴ v GM
e R
=^2At highest point vA = 0
Mechanical energy is conserved in the process.
Decrease in kinetic energy =^1
2mv^2
B
Increase in PE = UA – UB
VAGM
A Rh
= Potential at =
( + )−VBGM
RB =Potential at = 1.5^ RR 0.5 R(^3100)
2
2
−− −
= 3
21
299(^3100)
2 2
−−
GM
RRR−− GM −
RRGM(^3) R
2
×
2
[3 0.98]= × 2.02
2
∴−Increase in PE =
× (1.01)
GMm
Rh
GMm
R
Equate KE and PE.
1
2
( + )
mv^2 GMm +^ × 1.01
Rh
GMm
B R
−
GM
R
GM
Rh R
= 1
− + 1.01
or^1 =^1
++ 1.01
RRhR−or^1
+= 0.01 = 1Rh RR (^100)
or 100 R = R + h or h = 99R
- (a) : Let R be the radius of circular layer of water.
en pR^2 dρ = m
d
ATPressure at APT
d=− 0
2
(meniscus is cylindrical in
shape)Pressure between the plates is less than the
atmospheric pressure and so the plates are pressed
together.
F = Force of attraction = 'ρ × areaFT
d=×R
(^22)
π
=×^22 T = 2
dm
dTm
.ρ dρ=×××
××
=
−
−20210007
00110 1000
28
3(^24)
..
.
.N
- (c)
- (b) : Variation of acceleration due to gravity with
altitude
gg h
h Re=−
(^12) ; ∆g gh
Re
=
2
Variation of l with temperature = 'lLinear expansivity = ∆
∆l
l()θT l
ggl
gg
gT g
h g
=
−=−
=+
−
2211
212
ππ
∆∆∆/T ll
gT l
θ l
21 π= + =+
2∆∆
e clock shows correct time if Th = Tq , ∆
l ∆
lg
22 g=
Linear expansivity = ∆
l ∆
lg
gh
Rh(^1010) eeR
2
10 5
===
National Talent Search Examination
The Schedule of NTSE-2018-19
Stage Area Tentative DatesStage-I
(State)Last Date for Submission of
Application FormTo be notified by the
respective State/UT. May
vary from state to state.
Examination in Mizoram,
Meghalaya, Nagaland and
Andaman and Nicobar Islands03 th November, 2018
(Saturday)Examination in All other
States and Union Territories04 th November, 2018
(Sunday)West Bengal^18th November, 2018
(Sunday)
Stage-II
(National)Examination in All States and
Union Territories^12th May, 2019 (Sunday)