1549380323-Statistical Mechanics Theory and Molecular Simulation

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Appendix D Laplace transforms


The Laplace transform of a functionf(t) is just one of a general class of integral
transforms of the form


f ̃(s) =

∫∞


0

dt K(st)f(t), (D.1)

whereK(x) is a kernel that is typically a smooth and rapidly decaying function ofx.
The Laplace transform corresponds to the choiceK(x) = e−x.
Interestingly, even if the integral off(t) over the intervalt∈[0,∞) does not exist,
the Laplace transformf ̃(s) nevertheless can. If there exists a positive constants 0 such
that|e−s^0 tf(t)|≤MforMfinite, thenf ̃(s) exists fors > s 0. By contrast, a function
such asf(t) = exp(t^2 ) does not have a Laplace transform.
Laplace transforms of elementary functions are generally straightforward to evalu-
ate. Some examples are given below:


f(t) =tn, f ̃(s) =

n!
sn+1

,


f(t) = e−at, f ̃(s) =

1


s+a

,


f(t) = cos(ωt), f ̃(s) =

s
s^2 +ω^2

,


f(t) = sin(ωt), f ̃(s) =

ω
s^2 +ω^2

,


f(t) = cosh(αt), f ̃(s) =

s
s^2 −α^2

,


f(t) = sinh(αt), f ̃(s) =
α
s^2 −α^2

. (D.2)


In addition to these elementary transforms another useful result is the Laplace trans-
form of the convolutionf(t) between two functionsg(t) andh(t). Recall that this
convolution is defined as


f(t) =

∫t

0

dτ g(τ)h(t−τ). (D.3)

The Laplace transform off(t) isf ̃(s) = ̃g(s) ̃h(s), which is known as theconvolution
theorem. The proof of the convolution theorem proceeds by writing

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