82 Chapter 2 • Sequences
- Prove that if all terms of a convergent sequence { Xn} lie in a closed interval
[a, b], then its limit is also in [a, b]. What if [a, b] is changed to (a, b)? - Let e E JR. be fixed. Prove that Vp E N , if lei < 1, lim nPen = 0.
n->oo - '<Ix E JR., let [x] = the greatest integer less than or equal to x, and let
e E R Prove that
. [en]
(a) hm - = e.
n-+oo n
(b) If e > 0, lim [~] n = 0.
n--+oo en
2.4 Divergence to Infinity
Definition 2.4.1 Suppose {xn} is a sequence of real numbers. We say that
(a) {xn} diverges to +oo ( lim Xn = +oo) if
n->oo
VM > 0,3no EN 3 n 2: no==:> Xn > M;
(b) {xn} diverges to -oo ( lim Xn = -oo) if
n->oo
VM > 0, 3no EN 3 n 2: no==:> Xn < -M.
Note that this definition implies that if lim Xn = +oo (or -oo) then {xn}
n->oo
is unbounded, hence {xn} cannot converge (why?). So we will not say that {xn}
converges to +oo or -oo, or that lim Xn exists in these cases, even though we
n->oo
use the notation lim Xn.
n->oo
Example 2.4.2 Consider the limit statement lim (
3
n
2
2
n) = +oo.
· n->oo 5n + 23
3n^2 - 2n
(a) After how many terms are we guaranteed that > 100?
5n+ 23
(b) For arbitrary M > 0, after how many terms are we guaranteed that
3n^2 - 2n M?
--->.
5n+ 23
. 3n^2 - 2n
Solution: (a) We want an no EN 3 n > n 0 ==:> > 100. Now,
- 5n+ 23
3n^2 - 2n 3n^2 - 2n 'f
---> ,1n> 24
5n + 23 5n + n -
3n^2 - 2n
6
n , if n 2: 24
3n-2
- 6
- , if n 2: 24.