7.8 *Improper Riemann Integrals 437
Proof. Suppose l: f is an improper integral of Type I. We consider the
case in which f is integrable over every subinterval [c, b], where a < c < b. The
other cases have similar proofs. Now, \:/x E (a , b],
-lf(x)I :S f(x) :S lf(x)I, so
0 :S f(x) + lf(x)I :S 2lf(x)I. (45)
But l: Iii converges, by hypothesis, so l: 2lfl also converges. Hence, by
(45) and the comparison test, l: (f(x) + lf(x)I) converges.
Now, \:/a < c < b,
l: f = f:[U + lfl) - lfll = J:u + lfl) - J: Iii-
Then lim J: f exists, since both lim l:U + lfl) and lim l: Iii exist.
c--+a+ c--+a+ c--+a+
Therefore, l: f converges. •
EXERCISE SET 7.8-A
l. Suppose the hypotheses of Definition 7.8.1 are met: a < b and f is inte-
grable on every closed subinterval of the form [c, b], where a < c < b. But
suppose that f is not integrable on [a, b]. Prove that 3 c > 0 3 f is not
bounded on [a, a+ c). State a similar result about Definition 7.8.2.
- Prove that if f is integrable on [a, b], where a < b, then lim l: f = l: f
c-.a+
and c->lim b-;:c a f = t a f. - In each of the following, determine whether l: f is an improper integral
and, if so, determine its convergence or divergence. When possible, find
the values of those improper integrals that converge.
1
1 1
(a) - dx
0 x
fl 1
(b) Jo v'xdx 1
1 1
(c) - dx
o ex
1
2 1
(d) -
1
-dx
1 x nx
(e) fo
1
lnxdx (f)^13 x dx
l~