9.2 CHAPTER 9. GEOMETRY
Example 2: Circle Geometry II
QUESTIONABCDEFG HFD is drawn parallel to thetangent CBProve that:- FADE is cyclic
2.�AFE///�CBD3.FCGH×AG=DCBD×FESOLUTIONStep 1 : In this case, the best way to show FADE is a cyclic quadrilateral is to look for
equal angles, subtendedby the same chord.
Let∠BCD = x∴∠CAH = x (∠ between tangent BC and chord CE)
∴∠FDC = x (alternate∠, FD� CB)
∴ FADE is a cyclic quadrilateral(chord FE subtends equal∠’s)Step 2 : To show these 2 triangles similar we will need3 equal angles. We canuse the
result from the previousquestion.