Cracking the SAT Physics Subject Test

(Marvins-Underground-K-12) #1

The net force toward the center of the bob’s circular path is FT − mg


cosθmax. This must provide the centripetal force,. But since


the speed of the bob at this moment is zero (v = 0), we get FT = mg


cos θmax. (The acceleration is purely tangential here, equal to


= g sin θmax.)
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