Answer Key 229
- x^2 − x − 6 = 0
(x − 3) (x + 2) = 0
x − 3 = 0 or x + 2 = 0
x = 3 or x = −2 - x^2 + 6x + 9 = −5 + 9
(x + 3)^2 = 4
x + 3 = ± 2
x + 3 = 2 or x + 3 = −2
x = −1 or x = −5 - 3510
4
2
2
2
xx 5
x
55 x+
=−()−^5 ()^5 − ()^3 ()^1
() 3
x=^51 ±^3
6
- x^2 − 6 = 8
x^2 = 14
x=± 14 - x^2 − 3x+ 2 = 0
x=
−−( ) ( ) − ()( )
()
= −
(^33) )±−( (^41) ( 2
(^21) (
39 ± 8
2
2
x=
31 ±
2
x=^31 ±
2
x==
4
2
2 or x==
2
2
1
- 9x^2 + 18 x − 17 = 0
x=
−± − ()()−
()
18 18 4 (
2 (
2
x=−±^18936
18
x=
−± (^1836) ()
18
x=−±^18626
18
x=
− 32 ± 6
3
- 6x^2 − 12x + 7 = 0
x=
−()− ± ()− − ()()
()
=
±−
(^4) (
(^2) (
12 144 168
12
2
x=^12 ±−^24
12
There is no real solution because the
discriminant is negative.
Chapter 15 Solving Quadratic Equations
Exercise 15