Areas, Volumes, and Arc Lengths 285xyy = –3y = ex0–3ln 2Figure 12.4-11Step 2. Determine the radius from a cross section.
r=y−(−3)=y+ 3 =ex+ 3
Step 3. Set up an integral.V=π∫ln20(ex+ 3 )^2 dxStep 4. Evaluate the integral.
Enter∫ (
π(e∧(x)+ 3 )∧2, x, 0 ln (2))
and obtainπ(
9ln2+15
2
)= 13. 7383 π.The volume of the solid is approximately 13. 7383 π.TIP • Remember: iff′is increasing, thenf′′>0 and the graph offis concave upward.
The Washer Method
The volume of a solid (with a hole in the middle) generated by revolving a region bounded
by 2 curves:
About thex-axis:V=π∫ba[
(f(x))^2 −(g(x))^2]
dx; wheref(x)=outer radius andg(x)=inner radius.About they-axis:V=π∫dc[
(p(y))^2 −(q(y))^2]
dy; wherep(y)=outer radius andq(y)=inner radius.