More Applications of Definite Integrals 31313.2 Distance Traveled Problems
Summary of Formulas
Position Function:s(t);s(t)=∫
v(t)dt.Velocity:v(t)=
ds
dt
;v(t)=∫
a(t)dt.Acceleration:a(t)=
dv
dt.
Speed:|v(t)|.
Displacement fromt 1 tot 2 =∫t 2t 1v(t)dt=s(t 2 )−s(t 1 ).Total Distance Traveled fromt 1 tot 2 =∫t 2t 1∣∣
v(t)∣∣
dt.Example 1
See Figure 13.2-1.010–10202 4 6 8 10 12v(t)v(t)t
(seconds)(feet/sec)Figure 13.2-1The graph of the velocity function of a moving particle is shown in Figure 13.2-1.
What is the total distance traveled by the particle during 0≤t≤12?Total Distance Traveled=∣∣
∣
∣∫ 40v(t)dt∣∣
∣
∣+∫ 124v(t)dt=
1
2
(4)(10)+
1
2
(8)(20)= 20 + 80 =100 feet.Example 2
The velocity function of a moving particle on a coordinate line isv(t)=t^2 + 3 t− 10
for 0 ≤ t ≤ 6. Find (a) the displacement by the particle during 0 ≤ t ≤ 6, and
(b) the total distance traveled during 0≤t≤6.