Cracking The Ap Calculus ab Exam 2018

3. x^5 − x^3 + x^2 + 6x + C

Here we will use the Power Rule, which says that . The integral is ∫(5x^4 −

3 x^2   +   2x  +   6)  dx  =       +   6x  +   C   =   x^5     −   x^3     +   x^2     +   6x  +   C.

4.

Here    we  will    use the Power   Rule,   which   says    that     .  The integral    is

(^) ∫(3x−3 − 2x−2 + x^4 + 16x^7 ) dx = + C = + 2x^8 +

C.

5.

Here    we  will    use the Power   Rule,   which   says    that     .  First,  let’s   simplify    the

integrand:   dx  =   dx.     Now,    we  can     evaluate    the     integral:  

dx  =   .

6.

Here    we  will    use the Power   Rule,   which   says    that     .  First,  let’s   simplify    the

integrand: ∫(x^3 + x)^2 dx = ∫(x^6 + 2x^4 + x^2 ) dx. Now, we can evaluate the integral:

dx  =   .

7.