Cracking The Ap Calculus ab Exam 2018

and ∫cos x dx = sin x + C.

First,   we  need    to  rewrite     the     integrand,  using   trig    identities:     dx  =  

dx = ∫(cos x + 4 sec^2 x) dx. Now, we can evaluate the integral: ∫(cos x +

4   sec^2 x)    dx  =   sin x   +   4   tan x   +   C.

12. −2 cos x + C

Here we will use the Rules for the Integrals of Trig Functions, namely: ∫sin x dx = − cos x + C.

First,  we  need    to  rewrite the integrand,  using   trig    identities:     =       =   

. Now, we can evaluate the integral: ∫2 sin x dx = −2 cos x + C.

13. x + sin x + C

Here we will use the Rules for the Integrals of Trig Functions, namely: ∫cos x dx = sin x + C.

First, we need to rewrite the integrand, using trig identities: ∫(1 + cos^2 x sec x) dx =

dx = ∫(1 + cos x) dx. Now, we can evaluate the integral: ∫(1 + cos x) dx = x +

sin x   +   C.

14. − cos x + C

Here we will use the Rules for the Integrals of Trig Functions, namely: ∫sin x dx = − cos x + C.

First, we need to rewrite the integrand, using trig identities: dx = ∫ sin x dx. Now we

can evaluate the integral: ∫sin x dx = − cos x + C.

15. 
    

    −2  tan x   +   C

    
    

Here we will use the Rules for the Integrals of Trig Functions, namely: ∫sec^2 x dx = tan x + C.

First, we need to rewrite the integrand, using trig identities: ∫ dx = ∫(x − 2 sec^2