Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
Next,    we  need    to  find    where   the     two     curves  intersect,  which   will    be  the     endpoints   of  the

region.  We  do  this    by  setting     the     two     curves  equal   to  each    other.  We  get    x^2 −    2   =   2.  The

solutions   are (−2,    0)  and (2, 0). Therefore,  in  order   to  find    the area    of  the region, we  need    to

evaluate    the integral.   (2  −   (x^2    −   2)) dx  =       (4  −   x^2 )   dx. We  get

    (4  −   x^2 )   dx  =       −       =   .

2.

We  find    the area    of  a   region  bounded by  f(x)    above   and g(x)    below   at  all points  of  the interval

[a, b]  using   the formula     [f(x    −   g(x))]  dx. Here    f(x)    =   4x  −   x^2     and g(x)    =   x^2.

First,  let’s   make    a   sketch  of  the region.
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