11.5. Pyramids http://www.ck12.org
- In this example, we are given the slant height. For volume, we need the height, so we need to use the Pythagorean
Theorem to find it.
72 +h^2 = 252
h^2 = 576
h= 24
Using the height, the volume is^13 ( 142 )( 24 ) = 1568 units^3.
- The base of this pyramid is a right triangle. So, the area of the base is^12 ( 14 )( 8 ) = 56 units^2.
V=
1
3
( 56 )( 17 )≈ 317. 33 units^3
- The formula for the volume of a pyramid works for any pyramid, as long as you can find the area of the base.
224 = 56 h
4 =h
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Fill in the blanks about the diagram below.
1.xis the ___________.
- The slant height is ____.
3.yis the ___. - The height is ____.
- The base is ___.
- The base edge is ____.
Find the area of a lateral face and the volume of the regular pyramid. Leave your answer in simplest radical form.