AP Statistics 2017

(Marvins-Underground-K-12) #1


  1.              a.          



b.          For each    additional  year    of  age,    the height  (in cm) is  predicted   to  increase    by  6.36    cm.
c.

We  would   expect  the residual    for 5.5 to  be  in  the same    general area    as  the residuals   for 4,  5,  6,  and 7
(circled on the graph). The residuals in this area are all positive actual – predicted > 0 actual >
predicted. The prediction would probably be too small.



  1.          a.          It  is  an  observational   study.  The researcher  made    no  attempt to  impose  a   treatment   on  the subjects

    in the study. The hired person simply observed and recorded behavior.
    b. • The article made no mention of the sample size. Without that you are unable to judge how much
    sampling variability there might have been. It’s possible that the 63–59 split was attributable to
    sampling variability.
    • The study was done at one Scorebucks, on one morning, for a single 2-hour period. The
    population at that Scorebucks might differ in some significant way from the patrons at other
    Scorebucks around the city (and there are many, many of them). It might have been different on
    a different day or during a different time of the day. A single 2-hour period may not have been
    enough time to collect sufficient data (we don’t know because the sample size wasn’t given)
    and, again, a 2-hour period in the afternoon might have yielded different results.
    c. You would conduct the study at multiple Scorebucks, possibly blocking by location if you believe
    that might make a difference (i.e., would a working-class neighborhood have different
    preferences than the ritziest neighborhood?). You would observe at different times of the day
    and on different days. You would make sure that the total sample size was large enough to
    control for sampling variability (replication).



  2. From the information given, we have
    • P (hit the first and hit the second) = (0.4) (0.7) = 0.28
    • P (hit the first and miss the second) = (0.4) (0.3) = 0.12
    • P (miss the first and hit the second) = (0.6) (0.4) = 0.24
    • P (miss the first and miss the second) = (0.6) (0.6) = 0.36
    This information can be summarized in the following table:

Free download pdf