Beginning Algebra, 11th Edition

(Marvins-Underground-K-12) #1

(b)


Twice First Last
term term

(c)


The first and last terms are perfect squares.


and


Twice the product of the first and last terms of the binomial is


which is notthe middle term of


This trinomial is not a perfect square. In fact, the trinomial cannot be factored even


with the methods of the previous sections. It is a prime polynomial.


(d)


Factor out the common factor, 3z.
is a perfect square trinomial.

= 3 z 12 z+ 522 Factor. NOW TRY


= 3 z 312 z 22 + 212 z 2152 + 524 4 z^2 + 20 z+ 25


= 3 z 14 z^2 + 20 z+ 252


12 z^3 + 60 z^2 + 75 z


25 y^2 + 20 y+ 16.


2 # 5 y# 4 = 40 y,


5 y+ 4


25 y^2 = 15 y 22 16 = 42


25 y^2 + 20 y+ 16


9 m^2 - 24 m+ 16 = 13 m 22 + 213 m 21 - 42 + 1 - 422 = 13 m- 422


384 CHAPTER 6 Factoring and Applications


NOW TRY
EXERCISE 5
Factor each trinomial.


(a)


(b)


(c)


(d) 80 x^3 + 120 x^2 + 45 x


9 x^2 + 6 x+ 4

4 p^2 - 28 p+ 49

t^2 - 18 t+ 81

NOTE

1. The sign of the second term in the squared binomial is always the same as the sign


of the middle term in the trinomial.


2. The first and last terms of a perfect square trinomial must be positive,because


they are squares. For example, the polynomial cannot be a perfect


square, because the last term is negative.


3. Perfect square trinomials can also be factored by using grouping or the FOIL


method, although using the method of this section is often easier.


x^2 - 2 x- 1


OBJECTIVE 3 Factor a difference of cubes.We can factor a difference of


cubesby using the following pattern.


Factoring a Difference of Cubes

x^3 y^3  1 xy 21 x^2 xyy^22


This pattern for factoring a difference of cubes should be memorized.To see that


the pattern is correct, multiply


Multiply vertically.
(Section 5.5)

x^3 - y^3 Add.


x^3 +x^2 y+xy^2 x 1 x^2 +xy+y^22


- x^2 y - xy^2 - y^3 - y 1 x^2 +xy+y^22


x -y


x^2 + xy + y^2


1 x-y 21 x^2 + xy+ y^22.


NOW TRY ANSWERS



  1. (a)
    (b)
    (c)prime
    (d) 5 x 14 x+ 322


12 p- 722

1 t- 922

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