- B, C, E, and F Interpret the given information using properties of positives
and negatives. In the first inequality, the exponents are odd, meaning that the
sign of the bases is preserved. Thus if (x^3 )(y^5 ) > 0, then xy > 0. If xy > 0, then
x and y are both positive or both negative. In the second inequality, you know
that x^2 is always positive. Thus, z^3 < 0. If z^3 < 0, then z < 0. Now look at the
choices. Based on the inferences you made, B, C, E, and F must be true. - E Let c represent the cost of the lunch. The original cost per person for the
lunch is: c 5. After a friend drops out, the cost per person is c 4. The prompt
tells you that the cost per person after a friend drops out is $6 more than the
original cost per person. You can express this relationship algebraically as:
c
4 =
c
5 + 6
To get rid of the denominator, multiply through the equation by 20, the least
common multiple of 4 and 5. Arrive at:
5 c = 4c + 120
c = 120
14. C The outcome you are looking for is any combination of even-even-odd.
Since all three conditions must be met, you should calculate each individual
probability and multiply them. The probability of landing on even =^12 , and
the probability of landing on odd =^12. Thus, the probability of the outcome
even-even-odd = (^12 )(^12 )(^12 ) =^18. However, note that^18 represents the ordering
even-even-odd. The outcome in the question can be satisfied when the order
is even-even-odd, even-odd-even, or odd-even-even. Since there are three
arrangements that satisfy what the question is asking for, multiply^18 by 3 =^38.- B The point corresponding to expenses is above the point corresponding to
revenues for two of the years (2000 and 2001). The correct answer is B. - D First, calculate the percent change in profit for the two time periods. In
2007, the profit was approximately $18 million − $15 million = $3 million. In
2008, the profit was approximately $26 million − $12 million = $14 million.
The approximate percent change in profits from 2007 to 2008 was thus:
14 million − 3 million
3 million × 100 = 366.66%
In 2009, the profit was approximately $29 million − $18 million = $11 million.
The approximate percent change in profit from 2008 to 2009 was thus:
14 million − 11 million
14 million = 21.4%
Now the question is, 366.66 is approximately what percent greater than 21.4?
Use the percent change formula:
percent change = change in valueoriginal value × 100
Plug the values into the formula:
percent change = 366.66 – 21.421.4 × 100 = 1,613%
The closest answer is choice D.
66 PART 1 ■ GETTING STARTED01-GRE-Test-2018_001-106.indd 66 12/05/17 11:38 am