- D profit = revenue – cost. The change in profit during this time period would
be: −$3 million − $4 million = −$7 million. Since the change would distribute
evenly throughout the 10-year period, the change in the average would be:
change in profit/number of years = $7 million/10 = $700,000 - B When working with questions that provide only fractions or percents
and no given amounts, the best strategy is to plug in numbers. Since the list
price increases by^13 and by^12 , choose an original value for the list price that is
divisible by 2 and 3: 600. The price in 1998 was thus 600 +^13 (600) = 800. The
price in 2008 was 600 +^12 (600) = 900. Now use the percent change formula:
change
original × 100
The change is 900 − 800 = 100. The original value is the price of the home in
2008, which was 800. Arrive at:^100800 × 100 = 12.5%. - A If the frame has a uniform width of 3 inches, then each side of the frame
must measure x + 6 inches. The area of the larger square is thus (x + 6)^2.
Since each side of the photograph measures x inches, the area of the
photograph is x^2.
the area of the frame = the area of the larger square – the area of the
photograph
Thus the area of the frame = (x + 6)^2 – x^2. Since the area of the frame equals
the area of the photograph, you can arrive at the following equation:
(x + 6)^2 – x^2 = x^2. Add x^2 to both sides: (x + 6)^2 = 2x^2. - D With a “could be true” question, you need to identify a property for the
given unknown that is satisfied by only one of the choices. The distance
between the center of the circle and the point (10,2) is 7. Since (10,2) lies
outside of the circle, the radius must be less than 7. The distance between the
center of the circle and the point (3,8) is 6. Since the point (3,8) lies inside of
the circle, the radius of the circle must be greater than 6. The radius of the
circle is thus between 6 and 7. Of the choices, the only value between 6 and 7
is 6.5.
CHAPTER 2 ■ GRE DIAGNOSTIC TEST 6701-GRE-Test-2018_001-106.indd 67 12/05/17 11:38 am