1088 26 Equilibrium Statistical Mechanics. II. Statistical ThermodynamicsEXAMPLE26.2
Show that ln(N−1) differs from ln(N) by a term that is proportional to 1/N.
Solutionln(N−1)ln(N)+ln(
1 −
1
N)The Taylor series that represents ln(1−x)isln(1−x)ln(1)+1
1!(
dln(1−x)
dx)x 0x+O(x^2 ) 0 −x+O(x^2 )whereO(x^2 ) stands for terms that have powers ofxat least as great asx^2.ln(N−1)ln(N)−1
NExercise 26.4
Equation (26.1-27) can also be obtained by pretending thatNcan take on any real value and
performing the differentiation in Eq. (26.1-23). Carry out this differentiation.The Gibbs Energy of a Dilute Gas
The Gibbs energy is defined byGA+PV (26.1-28)
so thatG−NkBTln(z
N)
−NkBT+NkBTG−NkBTln(z
N)
(26.1-29)
Note thatGNμ (26.1-30)This is a version of Euler’s theorem, which is discussed in Part I of this textbook.PROBLEMS
Section 26.1: The Statistical Thermodynamics of a
Dilute Gas
26.1 Consider the two isotopic substances^17 O 2 and^16 O^18 O.
Round off the atomic masses in amu to the nearest integer.
Answer the following questions without detailed
calculation:
a.How will the translational partition functions of the two
molecules compare at equal volumes and equal
temperatures?