PQ,(1tan_μ)A,(1 0)
xyμ
OPQ,(1tan¡μ)A,(1 0) xyμ
O-^32 ¼ -¼ -¼ 2 ¼ 2 ¼^32 ¼ 2 ¼^52 ¼
P
Q,(1¡¡tanμ)A,(1 0)¡
xyμ
OxyA,() 10 ¡tan¡μQ,(1¡¡tanμ)
Pμ
cos¡μ
N11-1-1 tangentOsin¡μ238 Trigonometric functions (Chapter 9)We have seen that if P(cosμ,sinμ) is a point which is free
to move around the unit circle, and if [OP] is extended to meet
the tangent at A(1,0), the intersection between these lines
occurs at Q(1,tanμ).This enables us to define thetangent functiontanμ=sinμ
cosμForμin quadrant 2 , sinμ is positive and cosμ is negative
and so tanμ=
sinμ
cosμ
is negative.As before, [OP] is extended to meet the tangent at A at
Q(1,tanμ). We see that Q is below thex-axis.Forμin quadrant 3 , sinμ and cosμ are both negative and
so tanμ is positive. This is clearly demonstrated as Q is back
above thex-axis.Forμin quadrant 4 , sinμ is negative and cosμ is positive.
tanμ is again negative. We see that Q is below thex-axis.Discussion
#endboxedheadingWhat happens totanμwhen P is at(0,1)and(0,¡1)?D The tangent function
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Additional Mathematics
Y:\HAESE\CAM4037\CamAdd_09\238CamAdd_09.cdr Monday, 6 January 2014 4:42:08 PM BRIAN