430 Integration (Chapter 15)
Example 12 Self Tutor
Integrate with respect tox:
a 2 e^2 x¡e¡^3 x b 2 sin(3x) + cos(4x+¼)
a
Z
(2e^2 x¡e¡^3 x)dx
=2(^12 )e^2 x¡(¡^13 )e¡^3 x+c
=e^2 x+^13 e¡^3 x+c
b
Z
(2 sin(3x) + cos(4x+¼))dx
=¡^23 cos(3x)+^14 sin(4x+¼)+c
EXERCISE 15F
1 Find:
a
Z
(2x+5)^3 dx b
Z
1
(3¡ 2 x)^2
dx c
Z
4
(2x¡1)^4
dx
d
Z
(4x¡3)^7 dx e
Z p
3 x¡ 4 dx f
Z
10
p
1 ¡ 5 x
dx
g
Z
3(1¡x)^4 dx h
Z
4
p
3 ¡ 4 x
dx
2 Integrate with respect tox:
a sin(3x) b 2 cos(¡ 4 x)+1 c 3 cos
¡x
2
¢
d 3 sin(2x)¡e¡x e 2 sin
¡
2 x+¼ 6
¢
f ¡3 cos
¡¼
4 ¡x
¢
g cos(2x) + sin(2x) h 2 sin(3x) + 5 cos(4x) i^12 cos(8x)¡3 sinx
3 Find y=f(x) given
dy
dx
=
p
2 x¡ 7 and that y=11when x=8.
4 The function f(x) has gradient function f^0 (x)=
4
p
1 ¡x
, and the curve y=f(x) passes through
the point (¡ 3 ,¡11).
Find the point on the graph of y=f(x) withx-coordinate¡ 8.
5 Find:
a
Z
3(2x¡1)^2 dx b
Z
(x^2 ¡x)^2 dx c
Z
(1¡ 3 x)^3 dx
d
Z
(1¡x^2 )^2 dx e
Z
4
p
5 ¡xdx f
Z
(x^2 +1)^3 dx
6 Find:
a
Z ¡
2 ex+5e^2 x
¢
dx b
Z ¡
3 e^5 x¡^2
¢
dx c
Z ¡
e^7 ¡^3 x
¢
dx
d
Z
(ex+e¡x)^2 dx e
Z
(e¡x+2)^2 dx f
Z μ
x¡
5
(1¡x)^2
¶
dx
7 Find an expression forygiven that
dy
dx
=(1¡ex)^2 , and that the graph hasy-intercept 4.
=2£¡^13 cos(3x)+^14 sin(4x+¼)+c
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Additional Mathematics
Y:\HAESE\CAM4037\CamAdd_15\430CamAdd_15.cdr Monday, 7 April 2014 3:59:41 PM BRIAN