Cambridge International Mathematics

(Tina Sui) #1
728 ANSWERS

5a bx=¡ 4 ,x=1,
y=0
c x-intercept is 3
y-intercept is^34
d minimum turning
point at
¼(¡ 0 : 742 , 0 :659)
maximum turning
point at
¼(6: 74 , 0 :0607)

6ax¼ 2 : 18 b x¼ 3 : 29 c x¼ 0 : 505
7a¼(¡ 1 : 70 ,¡ 4 :94)and(1: 26 , 1 :98)
b¼(¡ 0 : 63 , 2 :50)and(0: 52 , 3 :76)

8a x f(x) g(x)
¡10 0:833 1: 25
¡ 50 :913 1: 118
01 1
51 :095 0: 894
10 1 : 20 : 8
15 1:315 0: 716
20 1 :44 0: 64

b forf(x):
largest is 1 : 44
smallest is 0 : 833
forg(x):
largest is 1 : 25
smallest is 0 : 64

c

d(0,1) ey=¡ 0 : 01 x+1
9 ¼ 3

EXERCISE 24A
1aScale:
1 cm ́ 10 km/h

bScale:
1 cm ́ 10 m/s

c Scale: 1 cm ́ 10 m

d

Scale: 1 cm ́ 10 m/s

2aScale: 1 cm ́ 15 Newtons

b Scale: 1 cm ́ 15 Newtons

3aScale:
1 cm ́ 20 km/h

b Scale:
1 cm ́ 15 kg m/s

c Scale:
1 cm ́ 10 km

d Scale:
1 cm ́ 30 km/h

EXERCISE 24B
1aa,cande; bandd b a,b,candd
c aandb; candd d none are equal
e aandc; bandd
2ap b¡p c q d¡q er f ¡r
3afalse btrue c false d true etrue
EXERCISE 24C
1a b

cd

ef

2a
¡!
QS b
¡!
PR c
¡!
PQ d
¡!
PS

y

x

x¡=¡-4 x¡=¡1

y¡=¡0
O

3 4

3

(^2) + -
= -
x x
y x
y
-10 20 x
1
g(x)=( 0. 8 )^10 x
f(x)=( 1. 2 )^10 x
O
N
E
S
W
45°
40 km/h
N
W E
S
35 m/s
N
W E
S
30°
120°
25 m
runway
12°
60 m/s
N
W E
S
75 Newtons
N
W E
S
45°
60 Newtons
N
W E
S
45°
60 km/h N
W E
S
45 kg m/s¡ 250°
N
W E
S
10°
90 km/h
N
W E
S
55° 25 km
p q
pq+
p q
pq+
p
q
pq+
q
p
p+q= 0
p
q
pq+
q
p
pq+
IB MYP_3 ANS
cyan magenta yellow black
(^05255075950525507595)
100 100
(^05255075950525507595)
100 100
Y:\HAESE\IGCSE01\IG01_an\728IB_IGC1_an.CDR Thursday, 20 November 2008 10:18:11 AM PETER

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