The Chemistry Maths Book, Second Edition

(Grace) #1

15.2 Orthogonal expansions 419


Therefore


and this is in agreement with the coefficient ofP


0

shown in (15.6).


0 Exercises 1, 2


The general case


Letg


n

(x),n 1 = 1 1, 2, 3, =, be a set of functions, possibly complex, that are orthogonal


in the intervala 1 ≤ 1 x 1 ≤ 1 bwith respect to the weight functionw(x):


(15.10)


(g*


m

1 = 1 g


m

for real functions). Letf(x)be an arbitrary function, defined in the interval


a 1 ≤ 1 x 1 ≤ 1 b, that can be expanded in the set{g


n

(x)},


(15.11)


Then, multiplication byg*


m

(x)and integration with respect to weight functionw(x)


in the interval ato bgives


so that (replacing mby n),


(15.12)


The denominator in this expression is the normalization integral of the function


g


n

(x); it is the square of the norm


(15.13)


g


gxgx xdx


n

a

b

nn

= Z


*() () ()w


c


gxfx xdx


gxgx xdx


n

a

b

n

a

b

nn

=


Z


Z


*
() () ()

*() () ()


w


w


=cgxgxxdx


m

a

b

mm

Z


*
() () ()w

ZZ


a

b

m

n

n

a

b

mn

gxfx xdx c gxgx


*
()() ()

*
ww= () () (

=


0


xxdx)


fx cg x


n

nn

()= ()


=


0


Z


a

b

mn

gxgx xdx*() () ()w =≠0ifmn


ca


aaa a


l


l

l

00

246

0

2

357 21


=++++=






=





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