The Chemistry Maths Book, Second Edition

(Grace) #1

15.6 Fourier transforms 439


EXAMPLE 15.10Find the Fourier transform of the exponential function, Figure


15.14(c),


f(x) 1 = 1 e


−ax

for x 1 > 1 0 and a 1 > 10


By equation (15.82),


The presence of a complex exponent does not alter the normal rule for the integration


of the exponential. Thus


becausee


−(a+iy)x

1 = 1 e


−ax

e


−iyx

1 → 1 0asx 1 → 1 ∞. The Fourier transform is complex and to


find the real part we write


Then


(15.83)


This function is called a Lorentzian, and gives the shapes of spectral lines in Fourier


transform spectroscopy.


0 Exercises 15–17


In applications in the physical sciences, the variables xand yare usually a pair of


conjugate variables. The most important of these are the coordinate–momentum


pair, such as the xcoordinate and its conjugate momentum, the linear momentum


p


x

, and the time–frequency (or time–energy) pair. A Fourier transformation is then


a transformation of the description of a physical system from one in the space


(or domain) of one of the variables of a conjugate pair to that of the other. The


momentum to coordinate Fourier transformation is an essential tool in the analysis


Regy


a


ay


()=














1


2


22

π


gy


aiy


aiyaiy


aiy


ay


()


()()


=



+−








=







1


2


1


2


22

ππ












gy


e


aiy aiy


aiyx

()


()

=















=








−+

1


2


1


2


1


0

ππ









=


+

−+

1


2


0

π


Z



edx


()aiyx

gy fxe dx e e dx


ixy ax ixy

()==()



+

−−−

1


2


1


2


0

ππ


ZZ



∞∞
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