Higher Engineering Mathematics

(Greg DeLong) #1
SOLUTION OF FIRST ORDER DIFFERENTIAL EQUATIONS BY SEPARATION OF VARIABLES 447

I

αis the temperature coefficient of resistance of
aluminium. IfR=R 0 whenθ= 0 ◦C, solve the
equation forR. (b) Ifα= 38 × 10 −^4 /◦C, deter-
mine the resistance of an aluminium conductor
at 50◦C, correct to 3 significant figures, when its
resistance at 0◦C is 24.0.

(a)

dR

=αRis of the form

dy
dx

=f(y)

Rearranging gives: dθ=

dR
αR

Integrating both sides gives:

dθ=


dR
αR

i.e., θ=

1
α

lnR+c,

which is the general solution.
Substituting the boundary conditions R=R 0
whenθ=0 gives:

0 =

1
α

lnR 0 +c

from whichc=−

1
α

lnR 0

Hence the particular solution is

θ=

1
α

lnR−

1
α

lnR 0 =

1
α

(lnR−lnR 0 )

i.e. θ=

1
α

ln

(
R
R 0

)
orαθ=ln

(
R
R 0

)

Hence eαθ=

R
R 0

from which,R=R 0 eαθ.

(b) Substitutingα= 38 × 10 −^4 ,R 0 = 24 .0 andθ=
50 intoR=R 0 eαθgives the resistance at 50◦C,
i.e.,R 50 = 24 .0e(38×^10


− (^4) ×50)
= 29 .0 ohms.
Now try the following exercise.
Exercise 179 Further problems on equa-
tions of the form
dy
dx
=f(y)
In Problems 1 to 3, solve the differential
equations.




  1. dy
    dx
    = 2 + 3 y
    [
    x=
    1
    3
    ln (2+ 3 y)+c
    ]




  2. dy
    dx
    =2 cos^2 y [ tany= 2 x+c]




  3. (y^2 +2)




dy
dx

= 5 y,giveny=1 whenx=

1
2
[
y^2
2

+2lny= 5 x− 2

]


  1. The current in an electric circuit is given by
    the equation


Ri+L

di
dt

=0,

whereL andR are constants. Show that
i=Ie

−Rt
L , given thati=Iwhent=0.


  1. The velocity of a chemical reaction is given


by

dx
dt

=k(a−x), wherex is the amount
transferred in timet,kis a constant anda
is the concentration at timet=0 whenx=0.
Solve the equation and determinexin terms
oft.[x=a(1−e−kt)]


  1. (a) ChargeQcoulombs at timetseconds
    is given by the differential equation


R

dQ
dt

+

Q
C

=0, whereCis the capaci-
tance in farads andRthe resistance in
ohms. Solve the equation forQgiven that
Q=Q 0 whent=0.

(b) A circuit possesses a resistance of
250 × 103  and a capacitance of
8. 5 × 10 −^6 F, and after 0.32 seconds the
charge falls to 8.0 C. Determine the ini-
tial charge and the charge after 1 second,
each correct to 3 significant figures.

[(a)Q=Q 0 e

−t
CR(b) 9.30 C, 5.81 C]


  1. A differential equation relating the difference
    in tensionT, pulley contact angleθand coeffi-


cient of frictionμis

dT

=μT. Whenθ=0,
T=150 N, andμ= 0 .30 as slipping starts.
Determine the tension at the point of slipping
whenθ=2 radians. Determine also the value
ofθwhenTis 300 N. [273.3 N, 2.31 rads]
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