Multiplying the above by and evaluating the expected value, we have
Kalman Filter Design: Lag 2
In order to enhance readability, we use and interchangeably to de-
note the posteriori state estimate. The state equation of the Kalman filter is
obtained as a first order approximation of the Taylor expansion about the
current point. To do that, an estimate of the derivative is required. The pre-
vious design used the first difference of the previous step as an estimate of
the derivative. In this design, the derivative is estimated with two sample
points. The mean and variance of the first sample are as follows:
The mean and variance of the second sample are as follows:
The covariance between the two samples are as follows:
The minimum variance linear combination of the two samples is given by
wherertis given as
rt =−
+−
var( ) cov( )
var( ) var( ) cov( )sample 2 samples
sample 1 sample 2 2 samplesrXtt(ˆˆ−− 12 −+− −Xt)( )( 1 r Xt tˆˆ−− 23 Xt)+cov()XXˆtt−− 23 ,ˆcov( ) cov ˆˆ, ˆˆcov( ) cov ˆ ,ˆ var ˆ cov ˆ ,ˆsamplessamples=−()()−
= ()− ()− ()+
−−−−−− − −−XXXX
XX X XX
ttt ttt t tt122312 2 13EXX
XX XX
tt
tt tt()ˆˆ
var( ) var ˆ var ˆ cov ˆ ,ˆsample 2
sample 2=+
= ()+ ()− ()
−−
−− −−23
232 23EXX
XX XX
tt
tt tt()ˆˆ
var( ) var ˆ var ˆ cov ˆ ,ˆsample1
sample1=−
= ()+ ()− ()
−−
−− −−12
122 12ˆ
Xt|t
Xˆ
tcov()XXˆtt−− −− 11 ||,ˆt t2 2=gt− (^1)  2 var()Xˆt t−−2 2|−cov()X Xˆt t−− −−2 2||,ˆtt 33
Xˆ
t− 2Spread Inversion 201
