144 Nodal and mesh analysis
Solution3 2
A=
5 1The product of the elements along the diagonal to the right is 3 x 1 = 3.
The product of the elements along the diagonal to the left is 2 • 5 = 10.
Therefore A = 3 - 10 = -7.Example 7.5
Find the determinant of the 3 • 3 matrix4I~ 240 ilSolution
A= 4 2 1
2 4 3
5 0 6
The sum of the products of the elements along the diagonals to the right is
(4x4x6)+(2x3x5)+ (1x2x0)=126
The sum of the products of the elements along the diagonals to the left is
(1•215215215215215
Therefore A = 126 - 44 = 82.
It might be found helpful to set out the elements of the determinant again
alongside the original one to see the three diagonals in each direction.The minor of an element
This is defined as the determinant of the submatrix obtained by deleting the
row and the column containing the element. Thus for the matrix21 a22 a23|
31 a32 a33.]
the minor of element a21 isa~2 a13
a32 a33