2 H• + 2 Cl• 2 H–Cl
10.2B HOMOLYTIC BOND DISSOCIATION ENERGIES AND THE RELATIVE
STABILITIES OF RADICALS:
- Bond dissociation energies can be used to eatimate the relative stabilities of
radicals.
∆H° for 1° and 2° C–H bonds of propane:
CH 3 CH 2 CH 2 –H (CH 3 ) 2 CH–H
(∆H° = 410 kJ mol–1) (∆H° = 395 kJ mol–1)
∆H° for the reactions:
CH 3 CH 2 CH 2 –H CH 3 CH 2 CH 2 • + H• ∆H° = + 410 kJ mol–1
Propyl radical
(a 1° radical)
(CH 3 ) 2 CH–H (CH 3 ) 2 CH• + H• ∆H° = + 395 kJ mol–1
Isopropyl radical
(a 2° radical)
3) These two reactions both begin with the same alkane (propane), and they both
produce an alkyl radical and a hydrogen atom.
4) They differ in the amount of energy required and in the type of carbon radical
produced.
- Alkyl radicals are classified as being 1°, 2°, or 3° on the basis of the carbon atom
that has the unpaired electron.
- More energy must be supplied to produce a 1° alkyl radical (the propyl radical)
from propane than is required to produce a 2° carbon radical (the isopropyl
radical) from the same compound ⇒ 1° radical has greater potential energy
⇒ 2° radical is the more stable radical.
- Comparison of the tert-butyl radical (a 3° radical) and the isobutyl radical (a 1°
radical) relative to isobutene:
- 3° radical is more than the 1° radical by 29 kJ mol–1.